如何使用python实现对DM二维码的矫正，并计算其中心坐标，偏移角度和二维码内容的0-1矩

阵？

实现步骤：

1. 导入相关库

import cv2
import numpy as np
from pyzbar.pyzbar import decode

2. 读取图像

img = cv2.imread('qr_code.png')

3. 灰度化处理

gray = cv2.cvtColor(img, cv2.COLOR_BGR2GRAY)

4. 二值化处理

_, thresh = cv2.threshold(gray, 0, 255, cv2.THRESH_BINARY+cv2.THRESH_OTSU)

5. 寻找轮廓

contours, _ = cv2.findContours(thresh, cv2.RETR_EXTERNAL, cv2.CHAIN_APPROX_NONE)

6. 计算最大轮廓的外接矩形

rect = cv2.minAreaRect(max(contours, key=cv2.contourArea))

7. 计算中心坐标和偏移角度

center, angle, _ = rect

8. 绘制矫正后的图像

h, w, _ = img.shape
M = cv2.getRotationMatrix2D(center, angle, 1)
img_rotated = cv2.warpAffine(img, M, (w, h))

9. 解码二维码

decoded = decode(img_rotated)

10. 计算二维码内容的0-1矩阵

code = decoded[0][0]
rows, cols = np.where(thresh==255)
min_row, max_row, min_col, max_col = min(rows), max(rows), min(cols), max(cols)
mask = np.zeros((max_row-min_row+1, max_col-min_col+1), dtype=np.uint8)
for i in range(code.shape[0]):
    for j in range(code.shape[1]):
        if code[i][j] == 1:
            x = int(center[0]-code.shape[1]*10/2+j*10)
            y = int(center[1]-code.shape[0]*10/2+i*10)
            mask[y-min_row:y-min_row+10, x-min_col:x-min_col+10] = 255

完整代码如下：

import cv2
import numpy as np
from pyzbar.pyzbar import decode

img = cv2.imread('qr_code.png')
gray = cv2.cvtColor(img, cv2.COLOR_BGR2GRAY)
_, thresh = cv2.threshold(gray, 0, 255, cv2.THRESH_BINARY+cv2.THRESH_OTSU)
contours, _ = cv2.findContours(thresh, cv2.RETR_EXTERNAL, cv2.CHAIN_APPROX_NONE)
rect = cv2.minAreaRect(max(contours, key=cv2.contourArea)))
center, angle, _ = rect
h, w, _ = img.shape
M = cv2.getRotationMatrix2D(center, angle, 1)
img_rotated = cv2.warpAffine(img, M, (w, h))
decoded = decode(img_rotated)
code = decoded[0][0]
rows, cols = np.where(thresh==255)
min_row, max_row, min_col, max_col = min(rows), max(rows), min(cols), max(cols)
mask = np.zeros((max_row-min_row+1, max_col-min_col+1), dtype=np.uint8)
for i in range(code.shape[0]):
    for j in range(code.shape[1]):
        if code[i][j] == 1:
            x = int(center[0]-code.shape[1]*10/2+j*10)
            y = int(center[1]-code.shape[0]*10/2+i*10)
            mask[y-min_row:y-min_row+10, x-min_col:x-min_col+10] = 255