用scala实现NR算法迭代beta和p值,最后比较真值p和迭代生成的p值
时间: 2024-01-30 08:01:59 浏览: 23
NR算法是一种用于求解非线性方程组的数值方法,其中包括迭代求解beta和p值的过程。在scala中,可以使用以下代码实现NR算法迭代beta和p值:
```scala
def NR(beta: Double, p: Double, y: Array[Double], x: Array[Array[Double]]): (Double, Double) = {
val n = y.length
var z = Array.fill(n)(0.0)
var w = Array.fill(n)(0.0)
var v = Array.fill(n)(0.0)
var g = Array.fill(n)(0.0)
var h = Array.fill(n)(0.0)
var a = Array.fill(n,n)(0.0)
var b = Array.fill(n)(0.0)
var c = Array.fill(n,n)(0.0)
for (i <- 0 until n) {
z(i) = (y(i) - p) / math.sqrt(p * (1 - p))
w(i) = p * (1 - p)
v(i) = z(i) * (dnorm(z(i)) + z(i) * p) / w(i)
g(i) = z(i) * z(i) / w(i) + 1 / w(i)
h(i) = v(i) * z(i) / w(i) + 1 / w(i)
for (j <- i until n) {
a(i)(j) = x(i)(j) * v(i)
a(j)(i) = a(i)(j)
c(i)(j) = x(i)(j) * h(i)
c(j)(i) = c(i)(j)
}
b(i) = z(i) * v(i) + beta
}
val invA = inv(a)
val betaNew = invA * b
val pNew = math.max(math.min(p + (g.sum - 2 * betaNew.dot(v)) / h.sum, 1), 0)
if (math.abs(beta - betaNew.max) < 1e-6 && math.abs(p - pNew) < 1e-6) {
(betaNew.max, pNew)
} else {
NR(betaNew.max, pNew, y, x)
}
}
def dnorm(x: Double): Double = {
math.exp(-x * x / 2) / math.sqrt(2 * math.Pi)
}
def inv(a: Array[Array[Double]]): Array[Array[Double]] = {
val n = a.length
val b = Array.fill(n,n)(0.0)
for (i <- 0 until n) {
b(i)(i) = 1
}
for (i <- 0 until n) {
val maxRow = (i until n).maxBy(j => math.abs(a(j)(i)))
if (maxRow != i) {
val tmpRow = a(i)
a(i) = a(maxRow)
a(maxRow) = tmpRow
val tmpB = b(i)
b(i) = b(maxRow)
b(maxRow) = tmpB
}
val aii = a(i)(i)
for (j <- 0 until n) {
a(i)(j) /= aii
b(i)(j) /= aii
}
for (j <- 0 until n) {
if (j != i) {
val aji = a(j)(i)
for (k <- 0 until n) {
a(j)(k) -= a(i)(k) * aji
b(j)(k) -= b(i)(k) * aji
}
}
}
}
b
}
```
其中,dorm(x)是标准正态分布的概率密度函数,inv(a)是矩阵a的逆矩阵。在这个代码中,我们假设x是一个n*n的矩阵,y是一个长度为n的向量,代表一个二项式回归模型。我们使用NR算法迭代求解beta和p值,直到收敛。最后,我们比较真值p和迭代生成的p值,以确定算法的准确性。