SELECT * FROM p_record WHERE create_time BETWEEN ('2020-06-10 10:40:58','2023-06-10 10:40:58'); 该sql存在什么问题

时间: 2024-03-12 21:44:02 浏览: 20
该 SQL 语句存在语法错误,应该使用 AND 连接两个时间点,而不是将它们放在括号内作为一个参数。正确的 SQL 语句应该是: ``` SELECT * FROM p_record WHERE create_time BETWEEN '2020-06-10 10:40:58' AND '2023-06-10 10:40:58'; ``` 注意,这里的时间点应该是数据库中 `create_time` 字段的数据类型,如果 `create_time` 的数据类型不是时间类型,那么这个 SQL 语句也会出现错误。同时,该 SQL 语句没有进行排序或限制查询结果的数量,这可能会导致查询结果很大,占用过多的系统资源。
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SELECT CUST_ID agentId, AGE_NAME agentName, countReleased, dayAmountReleased, CASE o.agelimitType WHEN '1' THEN TO_CHAR(o.agelimitNum) ELSE TO_CHAR(o.issueamtlimit) END countLimit, CASE o.agelimitType WHEN '1' THEN '不限' ELSE TO_CHAR(o.daylimitamount) END dayMaxCount FROM (SELECT m.CUST_ID, m.AGE_NAME, ad.countReleased, t.dayAmountReleased, d.daylimitamount, d.issueamtlimit, (SELECT AGE_LIMIT_NUM FROM P_ACT_ALLOW_MANAGER WHERE ACTIVITY_ID = #{activityId} AND rownum = 1 ) AS agelimitNum, (SELECT AGE_LIMIT_NUM_TYPE FROM P_ACT_MANAGER_ACTIVITY WHERE ACTIVITY_ID = #{activityId} ) AS agelimitType FROM (SELECT c1.CUST_ID, c1.AGE_NAME FROM (SELECT CUST_ID, AGE_NAME FROM PM_AGET_INFO START WITH CUST_ID = #{agetId} CONNECT BY PRIOR CUST_ID = FATH_CUST_ID ) c1 INNER JOIN (SELECT DISTINCT CUST_ID, AGE_NAME FROM PM_AGET_INFO START WITH CUST_ID in (SELECT CUST_ID FROM P_ACT_ALLOW_MANAGER WHERE ACTIVITY_ID = #{activityId} ) CONNECT BY PRIOR CUST_ID = FATH_CUST_ID ) c2 ON c1.CUST_ID = c2.CUST_ID ) m LEFT JOIN (SELECT CUST_ID, count(RECORD_ID) countReleased FROM P_ACT_MANAGER_RECORD WHERE ACTIVITY_ID = #{activityId} AND RECORD_STATUS NOT IN (2, 5) AND to_date(CREATE_TIME, 'yyyy-MM-dd hh24:mi:ss') BETWEEN to_date(#{beginTime}, 'yyyyMMddhh24miss') AND to_date(#{endTime}, 'yyyyMMddhh24miss') GROUP BY CUST_ID ) ad ON m.CUST_ID = ad.CUST_ID LEFT JOIN (SELECT AGE_ID cust_id, DAY_LIMIT_AMOUNT daylimitAmount, ISSUE_AMT_LIMIT issueAmtLimit FROM P_ACT_MANAGER_LIMIT_ALLOT WHERE ACT_ID =#{activityId} ) d ON m.CUST_ID = d.CUST_ID LEFT JOIN (SELECT CUST_ID, count(RECORD_ID) dayAmountReleased FROM P_ACT_MANAGER_RECORD WHERE ACTIVITY_ID =#{activityId} AND RECORD_STATUS NOT IN (2, 5) AND to_date(CREATE_TIME, 'yyyy-MM-dd hh24:mi:ss') BETWEEN to_date(#{todayBegin}, 'yyyyMMddhh24miss') AND to_date(#{todayend}, 'yyyyMMddhh24miss') GROUP BY CUST_ID ) t ON m.CUST_ID = t.CUST_ID) o WHERE 1 = 1 AND o.CUST_ID = #{agentId} AND o.AGE_NAME = #{agentName} ORDER BY o.countReleased DESC NULLS LAST 如何优化此段sql代码,使得更加简洁?

这段 SQL 代码可以进行以下优化: 1. 使用 WITH 子句来代替嵌套查询,增加可读性。 2. 使用 LEFT JOIN 和 COALESCE 函数来代替子查询,避免多次查询。 3. 使用 CASE WHEN THEN ELSE END 语句来代替 IF 函数。 优化后的 SQL 代码如下: WITH cte1 AS ( SELECT CUST_ID, AGE_NAME FROM PM_AGET_INFO START WITH CUST_ID = #{agetId} CONNECT BY PRIOR CUST_ID = FATH_CUST_ID ), cte2 AS ( SELECT DISTINCT CUST_ID, AGE_NAME FROM PM_AGET_INFO START WITH CUST_ID IN ( SELECT CUST_ID FROM P_ACT_ALLOW_MANAGER WHERE ACTIVITY_ID = #{activityId} ) CONNECT BY PRIOR CUST_ID = FATH_CUST_ID ), cte3 AS ( SELECT CUST_ID, count(RECORD_ID) countReleased FROM P_ACT_MANAGER_RECORD WHERE ACTIVITY_ID = #{activityId} AND RECORD_STATUS NOT IN (2, 5) AND to_date(CREATE_TIME, 'yyyy-MM-dd hh24:mi:ss') BETWEEN to_date(#{beginTime}, 'yyyyMMddhh24miss') AND to_date(#{endTime}, 'yyyyMMddhh24miss') GROUP BY CUST_ID ), cte4 AS ( SELECT CUST_ID, count(RECORD_ID) dayAmountReleased FROM P_ACT_MANAGER_RECORD WHERE ACTIVITY_ID =#{activityId} AND RECORD_STATUS NOT IN (2, 5) AND to_date(CREATE_TIME, 'yyyy-MM-dd hh24:mi:ss') BETWEEN to_date(#{todayBegin}, 'yyyyMMddhh24miss') AND to_date(#{todayend}, 'yyyyMMddhh24miss') GROUP BY CUST_ID ), cte5 AS ( SELECT AGE_LIMIT_NUM FROM P_ACT_ALLOW_MANAGER WHERE ACTIVITY_ID = #{activityId} AND rownum = 1 ), cte6 AS ( SELECT AGE_LIMIT_NUM_TYPE FROM P_ACT_MANAGER_ACTIVITY WHERE ACTIVITY_ID = #{activityId} ), cte7 AS ( SELECT AGE_ID cust_id, DAY_LIMIT_AMOUNT daylimitAmount, ISSUE_AMT_LIMIT issueAmtLimit FROM P_ACT_MANAGER_LIMIT_ALLOT WHERE ACT_ID =#{activityId} ) SELECT m.CUST_ID agentId, m.AGE_NAME agentName, COALESCE(ad.countReleased, 0) countReleased, COALESCE(t.dayAmountReleased, 0) dayAmountReleased, CASE WHEN o.agelimitType = '1' THEN TO_CHAR(o.agelimitNum) ELSE TO_CHAR(o.issueamtlimit) END countLimit, CASE WHEN o.agelimitType = '1' THEN '不限' ELSE TO_CHAR(o.daylimitamount) END dayMaxCount FROM cte1 m INNER JOIN cte2 c ON m.CUST_ID = c.CUST_ID AND m.AGE_NAME = c.AGE_NAME LEFT JOIN cte3 ad ON m.CUST_ID = ad.CUST_ID LEFT JOIN cte4 t ON m.CUST_ID = t.CUST_ID LEFT JOIN cte5 ON 1 = 1 LEFT JOIN cte6 ON 1 = 1 LEFT JOIN cte7 d ON m.CUST_ID = d.CUST_ID LEFT JOIN ( SELECT COALESCE(AGE_LIMIT_NUM, 0) agelimitNum, COALESCE(AGE_LIMIT_NUM_TYPE, '1') agelimitType FROM dual ) o ON 1 = 1 WHERE m.CUST_ID = #{agentId} AND m.AGE_NAME = #{agentName} ORDER BY COALESCE(ad.countReleased, 0) DESC NULLS LAST 这样可以使得代码更加简洁易读,并且避免了重复查询和嵌套查询的问题。

<select id="getToallocatedBusinessNum" resultType="Integer"> SELECT COUNT(DISTINCT(id)) AS toallocatedBusinessNum FROM `tb_business` WHERE id NOT IN ( SELECT assign_id FROM `tb_assign_record` WHERE create_time BETWEEN #{startTime} AND #{endTime} AND latest = 1 AND `type` = 1 ) AND create_time BETWEEN #{startTime} AND #{endTime} </select>写成外连接

可以将原先的子查询改写成一个左外连接,如下所示: ``` <select id="getToallocatedBusinessNum" resultType="Integer"> SELECT COUNT(DISTINCT b.id) AS toallocatedBusinessNum FROM `tb_business` b LEFT JOIN ( SELECT assign_id FROM `tb_assign_record` WHERE create_time BETWEEN #{startTime} AND #{endTime} AND latest = 1 AND `type` = 1 ) ar ON b.id = ar.assign_id WHERE ar.assign_id IS NULL AND b.create_time BETWEEN #{startTime} AND #{endTime} </select> ``` 这里使用了一个左外连接,将 `tb_business` 表和子查询的结果集进行连接,连接条件是 `tb_business.id = tb_assign_record.assign_id`,然后在 `WHERE` 子句中过滤掉 `tb_assign_record.assign_id IS NULL` 的记录,即未分配的业务。最后统计 `DISTINCT` 的业务数即可。

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select a.*, b.name activityName, c.name productName, c.member_max memberMax, d.status as complete, group_concat(if(e.face_value is null, "", e.face_value) separator "\n") as rewardAmount, group_concat(if(e.coupon_code is null, "", e.coupon_code ) separator "\n") as couponCode , group_concat(if(e.coupon_id is null, "", e.coupon_id) separator "\n") as caId from marketing_group_tool_group_member a left join marketing_group_tool_group_info d on a.group_id = d.id left join marketing_group_tool_activity b on a.activity_id = b.activity_id left join marketing_group_tool_product_base c on a.product_id = c.product_id left join marketing_group_tool_send_coupon_record e on (a.group_id = e.group_id and a.card_no = e.card_no) left join wx_recommend_organization organization on b.organization_id = organization.id where ((organization.tree_id between 2002000000000000 and 2002999999999999) or (organization.tree_id between 1000000000000000 and 1999999999999999) or (organization.tree_id between 2000000000000000 and 2999999999999999) or (organization.tree_id between 3000000000000000 and 3999999999999999) or (organization.tree_id between 4000000000000000 and 4999999999999999) or (organization.tree_id between 6000000000000000 and 6999999999999999) or (organization.tree_id between 5000000000000000 and 5999999999999999) or (organization.tree_id between 10000000000000000 and 10999999999999999) or (organization.tree_id between 8000000000000000 and 8999999999999999) or (organization.tree_id between 9000000000000000 and 9999999999999999) or (organization.tree_id between 11000000000000000 and 11999999999999999) or (organization.tree_id between 12000000000000000 and 12999999999999999) or (organization.tree_id between 13000000000000000 and 13999999999999999) or (organization.tree_id between 14000000000000000 and 14999999999999999) or (organization.tree_id between 15000000000000000 and 15999999999999999) or (organization.tree_id between 16000000000000000 and 16999999999999999) or (organization.tree_id between 17000000000000000 and 17999999999999999) ) and 1 = 1 group by a.id, a.activity_id , a.group_id , a.product_id , a.activity_referral_code, a.product_referral_code , a.openid , a.unionid , a.nickname , a.head_img , a.mobile , a.is_sub_buy , a.is_sub_progress , a.is_sub_success , a.sort , a.card_no , a.create_time , a.is_received_notice , a.is_received_progress , a.is_received_success , b.name, c.name, c.member_max , d.status order by a.id desc limit 0,20;

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