c语言一元多项式的加法的源码
时间: 2023-09-13 18:05:19 浏览: 147
### 回答1:
答案:#include <stdio.h>
int main()
{
int degree1, degree2, i;
int coeff1[10], coeff2[10], sum[10];
printf("输入一元多项式一的阶数:");
scanf("%d", °ree1);
printf("输入一元多项式一的系数:");
for(i=0;i<=degree1;i++)
scanf("%d",&coeff1[i]);
printf("输入一元多项式二的阶数:");
scanf("%d", °ree2);
printf("输入一元多项式二的系数:");
for(i=0;i<=degree2;i++)
scanf("%d",&coeff2[i]);
//将两个多项式相加,结果存在sum数组中
for(i=0;i<=degree1 || i<=degree2;i++)
sum[i] = coeff1[i] + coeff2[i];
printf("求和结果为:");
//打印输出sum数组
for(i=degree1>degree2?degree1:degree2;i>=0;i--)
{
if(sum[i] != 0)
printf("%dx^%d+", sum[i], i);
}
printf("\b \n");
return 0;
}
### 回答2:
下面是C语言实现一元多项式的加法的源代码:
```c
#include <stdio.h>
#include <stdlib.h>
// 定义多项式结构体
typedef struct node {
int coefficient; // 系数
int exponent; // 指数
struct node* next;
} Polynomial;
// 向多项式中插入项
Polynomial* insertTerm(Polynomial* head, int coefficient, int exponent) {
Polynomial* newTerm = (Polynomial*)malloc(sizeof(Polynomial));
newTerm->coefficient = coefficient;
newTerm->exponent = exponent;
newTerm->next = NULL;
if (head == NULL) {
head = newTerm;
} else {
Polynomial* current = head;
while (current->next != NULL) {
current = current->next;
}
current->next = newTerm;
}
return head;
}
// 打印多项式
void printPolynomial(Polynomial* head) {
Polynomial* current = head;
while (current != NULL) {
printf("%dx^%d", current->coefficient, current->exponent);
current = current->next;
if (current != NULL) {
printf(" + ");
}
}
printf("\n");
}
// 多项式相加
Polynomial* addPolynomial(Polynomial* poly1, Polynomial* poly2) {
Polynomial* sum = NULL;
while (poly1 != NULL && poly2 != NULL) {
if (poly1->exponent > poly2->exponent) {
sum = insertTerm(sum, poly1->coefficient, poly1->exponent);
poly1 = poly1->next;
} else if (poly1->exponent < poly2->exponent) {
sum = insertTerm(sum, poly2->coefficient, poly2->exponent);
poly2 = poly2->next;
} else {
int coefficientSum = poly1->coefficient + poly2->coefficient;
if (coefficientSum != 0) {
sum = insertTerm(sum, coefficientSum, poly1->exponent);
}
poly1 = poly1->next;
poly2 = poly2->next;
}
}
while (poly1 != NULL) {
sum = insertTerm(sum, poly1->coefficient, poly1->exponent);
poly1 = poly1->next;
}
while (poly2 != NULL) {
sum = insertTerm(sum, poly2->coefficient, poly2->exponent);
poly2 = poly2->next;
}
return sum;
}
int main() {
Polynomial* poly1 = NULL;
Polynomial* poly2 = NULL;
Polynomial* sum = NULL;
// 向多项式1中插入项
poly1 = insertTerm(poly1, 3, 2);
poly1 = insertTerm(poly1, 4, 1);
poly1 = insertTerm(poly1, 2, 0);
// 向多项式2中插入项
poly2 = insertTerm(poly2, 2, 4);
poly2 = insertTerm(poly2, -1, 2);
poly2 = insertTerm(poly2, 5, 1);
poly2 = insertTerm(poly2, 3, 0);
// 多项式相加
sum = addPolynomial(poly1, poly2);
// 打印结果
printf("多项式1:");
printPolynomial(poly1);
printf("多项式2:");
printPolynomial(poly2);
printf("相加结果:");
printPolynomial(sum);
return 0;
}
```
这段代码实现了一元多项式的加法。程序定义了一个多项式结构体,其中包括系数和指数两个成员。程序首先实现了一个向多项式中插入项的函数`insertTerm`,然后定义了一个打印多项式的函数`printPolynomial`。接下来的`addPolynomial`函数实现了多项式的加法,最后在`main`函数中调用这些函数进行测试。
### 回答3:
以下是一元多项式加法的C语言源码:
```c
#include <stdio.h>
#include <stdlib.h>
typedef struct {
float coef;
int exp;
} Term;
typedef struct {
int numTerms;
Term* terms;
} Polynomial;
void polynomialAddition(Polynomial p1, Polynomial p2, Polynomial* result) {
int i = 0, j = 0, k = 0;
while (i < p1.numTerms && j < p2.numTerms) {
if (p1.terms[i].exp > p2.terms[j].exp) {
result->terms[k++] = p1.terms[i++];
} else if (p1.terms[i].exp < p2.terms[j].exp) {
result->terms[k++] = p2.terms[j++];
} else {
result->terms[k].coef = p1.terms[i].coef + p2.terms[j].coef;
result->terms[k].exp = p1.terms[i].exp;
i++;
j++;
k++;
}
}
// 把未操作完的项依次添加到结果多项式中
while (i < p1.numTerms) {
result->terms[k++] = p1.terms[i++];
}
while (j < p2.numTerms) {
result->terms[k++] = p2.terms[j++];
}
result->numTerms = k;
}
int main() {
Polynomial poly1, poly2, result;
int i;
printf("请输入第一个多项式的项数:");
scanf("%d", &poly1.numTerms);
poly1.terms = (Term*)malloc(poly1.numTerms * sizeof(Term));
printf("请输入第一个多项式的每一项的系数和指数:\n");
for (i=0; i<poly1.numTerms; i++) {
scanf("%f%d", &poly1.terms[i].coef, &poly1.terms[i].exp);
}
printf("请输入第二个多项式的项数:");
scanf("%d", &poly2.numTerms);
poly2.terms = (Term*)malloc(poly2.numTerms * sizeof(Term));
printf("请输入第二个多项式的每一项的系数和指数:\n");
for (i=0; i<poly2.numTerms; i++) {
scanf("%f%d", &poly2.terms[i].coef, &poly2.terms[i].exp);
}
result.terms = (Term*)malloc((poly1.numTerms + poly2.numTerms) * sizeof(Term));
polynomialAddition(poly1, poly2, &result);
printf("多项式相加的结果为:\n");
for (i=0; i<result.numTerms; i++) {
printf("%.2f*x^%d ", result.terms[i].coef, result.terms[i].exp);
if (i != result.numTerms-1) {
printf("+ ");
}
}
free(poly1.terms);
free(poly2.terms);
free(result.terms);
return 0;
}
```
这段代码定义了两个结构体Term和Polynomial,Term结构体用于表示多项式的一个项,包括系数和指数;Polynomial结构体用于表示多项式,包括项的数量和一个指向Term结构体数组的指针。
函数polynomialAddition用于执行多项式的加法操作,它接受两个多项式p1和p2以及一个指向结果多项式的指针。函数中使用了三个指针i、j和k来分别遍历p1、p2的项以及结果多项式的项。当p1和p2的当前指数相同时,将两个项的系数相加,并将结果添加到结果多项式中;否则,将较大指数的项添加到结果多项式中,直到遍历完其中一个多项式。最后,再将未遍历完的多项式的项依次添加到结果多项式中。
在main函数中,先读入用户输入的两个多项式,然后调用polynomialAddition函数进行相加操作,最后输出结果多项式。
注意:上述代码中只实现了多项式的加法,没有进行输入的验证和错误处理。在实际应用中,需要根据具体需求进行适当的修改和完善。
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