帮我生成一个python的扫雷游戏

好的，这里提供一个简单的扫雷游戏的Python代码，你可以在此基础上进行修改和完善：

import random
import pygame
 
# 初始化
pygame.init()
 
# 设置游戏窗口大小
screen = pygame.display.set_mode((240, 240))
 
# 设置游戏标题
pygame.display.set_caption("扫雷")
 
# 加载图片
tile = pygame.image.load("images/tile.png")
mine = pygame.image.load("images/mine.png")
flag = pygame.image.load("images/flag.png")
 
# 设置字体
font = pygame.font.Font(None, 24)
 
# 设置游戏变量
grid_size = 10
mine_count = 10
mine_list = []
tile_list = []
flag_list = []
game_over = False
game_win = False
 
# 随机生成地雷
for i in range(mine_count):
    mine_x = random.randint(0, grid_size - 1)
    mine_y = random.randint(0, grid_size - 1)
    if (mine_x, mine_y) not in mine_list:
        mine_list.append((mine_x, mine_y))
 
# 设置方格类
class Tile():
    def __init__(self, x, y):
        self.x = x
        self.y = y
        self.width = tile.get_rect().width
        self.height = tile.get_rect().height
        self.mine = False
        self.adjacent_count = 0
        self.revealed = False
        self.flagged = False
 
    def draw(self):
        if self.flagged:
            screen.blit(flag, (self.x * self.width, self.y * self.height))
        elif not self.revealed:
            screen.blit(tile, (self.x * self.width, self.y * self.height))
        elif self.mine:
            screen.blit(mine, (self.x * self.width, self.y * self.height))
        else:
            text = font.render(str(self.adjacent_count), True, (0, 0, 0))
            screen.blit(text, (self.x * self.width + 5, self.y * self.height + 5))
 
# 初始化方格列表
for x in range(grid_size):
    for y in range(grid_size):
        tile_list.append(Tile(x, y))
 
# 计算每个方格周围地雷数量
for tile in tile_list:
    if (tile.x, tile.y) in mine_list:
        tile.mine = True
    for i in range(-1, 2):
        for j in range(-1, 2):
            if (tile.x + i, tile.y + j) in mine_list:
                tile.adjacent_count += 1
 
# 设置主循环
while True:
    # 绘制方格
    for tile in tile_list:
        tile.draw()
 
    # 判断游戏是否结束
    if game_over:
        text = font.render("Game Over", True, (255, 0, 0))
        screen.blit(text, (80, 100))
    elif game_win:
        text = font.render("You Win", True, (0, 255, 0))
        screen.blit(text, (80, 100))
 
    # 事件处理
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            pygame.quit()
            exit()
        elif event.type == pygame.MOUSEBUTTONDOWN and not game_over and not game_win:
            x, y = pygame.mouse.get_pos()
            tile_x = x // tile.get_rect().width
            tile_y = y // tile.get_rect().height
            if event.button == 1:
                if (tile_x, tile_y) in mine_list:
                    game_over = True
                else:
                    tile_list[tile_y * grid_size + tile_x].revealed = True
                    if tile_list[tile_y * grid_size + tile_x].adjacent_count == 0:
                        for i in range(-1, 2):
                            for j in range(-1, 2):
                                if (tile_x + i, tile_y + j) not in mine_list and 0 <= tile_x + i < grid_size and 0 <= tile_y + j < grid_size:
                                    tile_list[(tile_y + j) * grid_size + tile_x + i].revealed = True
            elif event.button == 3:
                flag_list.append((tile_x, tile_y))
                tile_list[tile_y * grid_size + tile_x].flagged = True
 
    # 绘制旗帜
    for flag_x, flag_y in flag_list:
        screen.blit(flag, (flag_x * tile.get_rect().width, flag_y * tile.get_rect().height))
 
    # 判断是否胜利
    if all(tile.revealed or tile.mine for tile in tile_list):
        game_win = True
 
    # 刷新屏幕
    pygame.display.update()

你可以将这段代码保存为一个Python文件，然后将所需的图片放在`images`文件夹下运行。注意：本代码中没有设置计时器等功能，需要自己添加。