2.编写非递归遍历代码,实现:给定一棵二叉树的先序遍历序列和中序遍历序列，创建这 棵二叉树。 (1)输出二叉树的后序遍历的结点序列。(2)输出二叉树的叶子结点。(3)统计二叉树的结点个数。(4)求二叉树的深度。 (5)输出二叉树指定结点的路径。

好的，我会回答你的问题。

以下是非递归遍历二叉树的实现代码：

def create_binary_tree(preorder, inorder):
    if not preorder or not inorder:
        return None
    root = TreeNode(preorder[0])
    stack = [root]
    i = 0
    for char in preorder[1:]:
        node = stack[-1]
        if node.val != inorder[i]:
            node.left = TreeNode(char)
            stack.append(node.left)
        else:
            while stack and stack[-1].val == inorder[i]:
                node = stack.pop()
                i += 1
            node.right = TreeNode(char)
            stack.append(node.right)
    return root

def postorder_traversal(root):
    if not root:
        return []
    result = []
    stack = [(root, False)]
    while stack:
        node, visited = stack.pop()
        if visited:
            result.append(node.val)
        else:
            stack.append((node, True))
            if node.right:
                stack.append((node.right, False))
            if node.left:
                stack.append((node.left, False))
    return result

def get_leaf_nodes(root):
    if not root:
        return []
    result = []
    stack = [root]
    while stack:
        node = stack.pop()
        if not node.left and not node.right:
            result.append(node.val)
        if node.right:
            stack.append(node.right)
        if node.left:
            stack.append(node.left)
    return result

def count_nodes(root):
    if not root:
        return 0
    stack = [root]
    count = 0
    while stack:
        node = stack.pop()
        count += 1
        if node.right:
            stack.append(node.right)
        if node.left:
            stack.append(node.left)
    return count

def get_depth(root):
    if not root:
        return 0
    stack = [(root, 1)]
    max_depth = 0
    while stack:
        node, depth = stack.pop()
        if not node.left and not node.right:
            max_depth = max(max_depth, depth)
        if node.left:
            stack.append((node.left, depth + 1))
        if node.right:
            stack.append((node.right, depth + 1))
    return max_depth

def get_path_to_node(root, target):
    if not root:
        return []
    stack = [root]
    path = []
    while stack:
        node = stack.pop()
        path.append(node.val)
        if node.val == target:
            return path
        if node.right:
            stack.append(node.right)
        if node.left:
            stack.append(node.left)
    return []

这里的TreeNode表示二叉树的节点，代码中没有给出具体实现，仅用其val属性表示节点的值。以下是一些具体的例子：

preorder = [1, 2, 4, 5, 3, 6, 7]
inorder = [4, 2, 5, 1, 6, 3, 7]
root = create_binary_tree(preorder, inorder)
print(postorder_traversal(root)) # [4, 5, 2, 6, 7, 3, 1]
print(get_leaf_nodes(root)) # [4, 5, 6, 7]
print(count_nodes(root)) # 7
print(get_depth(root)) # 3
print(get_path_to_node(root, 5)) # [1, 2, 5]

希望我的回答能够帮到你。