The lower three bits (i.e. 2,1,0) of the Address Byte will contain peripheral specific commands.

时间: 2024-05-29 19:12:47 浏览: 103
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LCD.rar_stm32 .s contain

This statement is not necessarily true. The lower three bits of the Address Byte may contain peripheral specific commands in some communication protocols, but not all. It depends on the specific protocol being used.
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请用python语言实现以下问题并给出解题思路：As a example, consider the text THE CAT IN THE HAT. In this text, the letter T and the space character both occur with the highest frequency, so they will clearly have the shortest encoding bit patterns in an optimal encoding. The letters C, I and N only occur once, however, so they will have the longest codes. There are many possible sets of prefix-free variable-length bit patterns that would yield the optimal encoding, that is, that would allow the text to be encoded in the fewest number of bits. One such optimal encoding is to encode spaces with 00, A with 100, C with 1110, E with 1111, H with 110, I with 1010, N with 1011 and T with 01. The optimal encoding therefore requires only 51 bits compared to the 144 that would be necessary to encode the message with 8-bit ASCII encoding, a compression ratio of 2.8 to 1. Input The input file will contain a list of text strings, one per line. The text strings will consist only of uppercase alphanumeric characters and underscores (which are used in place of spaces). The end of the input will be signalled by a line containing only the word END as the text string. This line should not be processed. Output For each text string in the input, output the length in bits of the 8-bit ASCII encoding, the length in bits of an optimal prefix-free variable-length encoding, and the compression ratio accurate to one decimal point.

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Description Consider the following 5 picture frames placed on an 9 x 8 array. ........ ........ ........ ........ .CCC.... EEEEEE.. ........ ........ ..BBBB.. .C.C.... E....E.. DDDDDD.. ........ ..B..B.. .C.C.... E....E.. D....D.. ........ ..B..B.. .CCC.... E....E.. D....D.. ....AAAA ..B..B.. ........ E....E.. D....D.. ....A..A ..BBBB.. ........ E....E.. DDDDDD.. ....A..A ........ ........ E....E.. ........ ....AAAA ........ ........ EEEEEE.. ........ ........ ........ ........ 1 2 3 4 5 Now place them on top of one another starting with 1 at the bottom and ending up with 5 on top. If any part of a frame covers another it hides that part of the frame below. Viewing the stack of 5 frames we see the following. .CCC.... ECBCBB.. DCBCDB.. DCCC.B.. D.B.ABAA D.BBBB.A DDDDAD.A E...AAAA EEEEEE.. In what order are the frames stacked from bottom to top? The answer is EDABC. Your problem is to determine the order in which the frames are stacked from bottom to top given a picture of the stacked frames. Here are the rules: 1. The width of the frame is always exactly 1 character and the sides are never shorter than 3 characters. 2. It is possible to see at least one part of each of the four sides of a frame. A corner shows two sides. 3. The frames will be lettered with capital letters, and no two frames will be assigned the same letter. Input Each input block contains the height, h (h<=30) on the first line and the width w (w<=30) on the second. A picture of the stacked frames is then given as h strings with w characters each. Your input may contain multiple blocks of the format described above, without any blank lines in between. All blocks in the input must be processed sequentially. Output Write the solution to the standard output. Give the letters of the frames in the order they were stacked from bottom to top. If there are multiple possibilities for an ordering, list all such possibilities in alphabetical order, each one on a separate line. There will always be at least one legal ordering for each input block. List the output for all blocks in the input sequentially, without any blank lines (not even between blocks). Sample Input 9 8 .CCC.... ECBCBB.. DCBCDB.. DCCC.B.. D.B.ABAA D.BBBB.A DDDDAD.A E...AAAA EEEEEE.. Sample Output EDABC

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帮我写出以下java代码：The clearInvisibles method takes as argument the width w and the height h of the window, and deletes from the arraylist of bubbles any bubble which is not visible in the window anymore. For each bubble which is deleted, the score decreases by 1. WARNING: when you use the remove method of Java’s ArrayList class to remove an element of an arraylist at index i, the arraylist immediately shifts down by one position all the elements with higher indexes to make the arraylist one element shorter. So, for example, when removing the element at index i, the element at index i+1 immediately moves to the position at index i, the element at index i+2 immediately moves to the position at index i+1, etc. This means that on the next iteration of the loop, when i has become i+1, the element that you will be testing at index i+1 is in fact the element that used to be at index i+2. Which means that the element that used to be at index i+1 (and which is now at index i) will never be tested! Therefore, when removing elements from an arraylist, if your loop starts at index 0 and goes up the indexes in the arraylist, then your loop will fail to test some elements! CONCLUSION: when removing elements from an arraylist, your loop must start from the END of the arraylist and go DOWN to index 0. The deleteBubblesAtPoint method takes as argument the coordinates (x, y) of a point, and deletes from the arraylist of bubbles any bubble which contains this point (multiple bubbles might contain the point, because bubbles can overlap in the window). For each bubble which is deleted, the score increases by 1. The drawAll method draws all the bubbles in the arraylist of bubbles. Make sure you test as many methods of the Model class as poss

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Copil Copac is given a list of n−1 edges describing a tree of n vertices. He decides to draw it using the following algorithm: Step 0 : Draws the first vertex (vertex 1 ). Go to step 1 . Step 1 : For every edge in the input, in order: if the edge connects an already drawn vertex u to an undrawn vertex v , he will draw the undrawn vertex v and the edge. After checking every edge, go to step 2 . Step 2 : If all the vertices are drawn, terminate the algorithm. Else, go to step 1 . A reading is defined as the number of times Copil Copac performs step 1 . Find the number of readings needed by Copil Copac to draw the tree. Input Each test contains multiple test cases. The first line of input contains a single integer t (1≤t≤104 ) — the number of test cases. The description of test cases follows. The first line of each test case contains a single integer n (2≤n≤2⋅105 ) — the number of vertices of the tree. The following n−1 lines of each test case contain two integers ui and vi (1≤ui,vi≤n , ui≠vi ) — indicating that (ui,vi) is the i -th edge in the list. It is guaranteed that the given edges form a tree. It is guaranteed that the sum of n over all test cases does not exceed 2⋅105 . Output For each test case, output the number of readings Copil Copac needs to draw the tree.

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string name = query.substr(1, query.size() - 2); if (curses.count(name)) { cout [name] ; } else { cout ; } } else { // 根据效果查询对应咒语名称 bool found = false; for (auto it = curses.begin...

(Telephone Number Word Generator) Standard telephone keypads contain the digits 0 through 9. The numbers 2 through 9 each have three letters associated with them, as is indicated by the following table: Many people find it difficult to memorize phone numbers, so they use the correspondence between digits and letters to develop seven-letter words that correspond to their phone numbers. For example, a person whose telephone number is 686-2377 might use the correspondence indi- cated in the above table to develop the seven-letter word “NUMBERS.” Businesses frequently attempt to get telephone numbers that are easy for their clients to remember. If a business can advertise a simple word for its customers to dial, then no doubt the business will receive a few more calls. Each seven-letter word corresponds to exactly one seven-digit telephone number. The restaurant wishing to increase its take-home business could surely do so with the number 825-3688 (i.e., “TAKEOUT”). Each seven-digit phone number corresponds to many separate seven-letter words. Unfortunately, most of these represent unrecognizable juxtaposi- tions of letters. It’s possible, however, that the owner of a barber shop would be pleased to know that the shop’s telephone number, 424-7288, corresponds to “HAIRCUT.” A veterinarian with the phone number 738-2273 would be happy to know that the number corresponds to “PETCARE.” Write a program that, given a seven-digit number, writes to a file every possible seven-letter word corresponding to that number. There are 2187 (3 to the seventh power) such words. Avoid phone numbers with the digits 0 and 1.

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Your task is to sort a given string. Each word in the string will contain a single number. This number is the position the word should have in the result. Note: make a javascript program.Numbers can be from 1 to 9. So 1 will be the first word (not 0). If the input string is empty, return an empty string. The words in the input String will only contain valid consecutive numbers. Examples "is2 Thi1s T4est 3a" --> "Thi1s is2 3a T4est" "4of Fo1r pe6ople g3ood th5e the2" --> "Fo1r the2 g3ood 4of th5e pe6ople" "" --> ""

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用c++解决1080. Map Coloring Time limit: 1.0 second Memory limit: 64 MB We consider a geographical map with N countries numbered from 1 to N (0 < N < 99). For every country we know the numbers of other countries which are connected with its border. From every country we can reach to any other one, eventually crossing some borders. Write a program which determines whether it is possible to color the map only in two colors — red and blue in such a way that if two countries are connected their colors are different. The color of the first country is red. Your program must output one possible coloring for the other countries, or show, that such coloring is impossible. Input On the first line is written the number N. On the following N lines, the i-th line contains the countries to which the i-th country is connected. Every integer on this line is bigger than i, except the last one which is 0 and marks that no more countries are listed for country i. If a line contains 0, that means that the i-th country is not connected to any other country, which number is larger than i. Output The output contains exactly one line. If the coloring is possible, this line must contain a list of zeros and ones, without any separators between them. The i-th digit in this sequence is the color of the i-th country. 0 corresponds to red color, and one — to blue color. If a coloring is not possible, output the integer −1.

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写一个程序，并在代码中加入中文注释 - The input txt file has 3 lines. The first line has only one integer, the capacity of the bag. The second line has a bunch of positive integers for the value of each item. Two integers are separated by a comma “,”. The third line is in the same format as the second for the weight of each item. - When the calculation is finished, print the optimal value and optimal solution(s) one for each line on the screen. (The optimal value is unique, but the optimal solution may not.) - Sort the items in the optimal solution(s) in the decreasing order of item indices. - The index of items starts from 1. In your program, you need to implement three source files “main.cpp”, “lib.h” and “lib.cpp” For “main.cpp” - It only contains the “main” function. - It reads inputs from .txt files. The input txt file is passed to the main function as an argument. - Each txt file contains exactly one instance. For “lib.h” and “lib.cpp” - .h is the header file for .cpp. - They contain all other functions except “main”.

dp[i][j] = max(dp[i-1][j], dp[i-1][j-items[i-1].weight] + items[i-1].value); } } } // 返回最优解 return dp[n][capacity]; } void backtrack(vector<Item>& items, vector<vector<int>>& dp, vector...
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