def monty_choice(car, contestant): # this method simulates Monty opening an door behind which there is a goat # Parameters # car, which is either 1, 2 or 3, represents the door behind which is a car # contestant, which is either 1, 2 or 3, represents the door that contestant chooses # Returns # an integer, which is 1,2 or 3, represents the door that host chooses to open # write your code below this line。请帮我完成需要填写的代码
时间: 2024-03-27 20:39:34 浏览: 20
```python
def monty_choice(car, contestant):
# create a list of doors
doors = [1, 2, 3]
# remove the car and contestant's choice from the list
doors.remove(car)
if contestant in doors:
doors.remove(contestant)
# open one of the remaining doors randomly
return random.choice(doors)
```
这段代码首先创建了一个包含三个元素的列表 `doors`,分别代表三个门。然后,它从列表中删除了 `car` 和 `contestant`,剩下的就是Monty可以选择的门。如果Monty选择的门已经在 `doors` 列表中,那么也要将它从列表中删除。最后,从剩下的门中随机选择一扇门打开,并将其返回。注意,这里我们需要使用 Python 自带的 `random` 模块中的 `choice()` 函数来随机选择一个元素。
相关问题
def monty_choice(car, contestant): # this method simulates Monty opening an door behind which there is a goat # Parameters # car, which is either 1, 2 or 3, represents the door behind which is a car # contestant, which is either 1, 2 or 3, represents the door that contestant chooses # Returns # an integer, which is 1,2 or 3, represents the door that host chooses to open # write your code below this line
Here's one possible implementation of the `monty_choice` function in Python:
```python
def monty_choice(car, contestant):
# find the door that Monty can open
options = [1, 2, 3]
options.remove(car)
if contestant in options:
options.remove(contestant)
door_to_open = random.choice(options)
return door_to_open
```
This function takes in two parameters: `car` and `contestant`, which represent the door behind which is a car and the door that the contestant chooses, respectively. It returns an integer, which represents the door that Monty chooses to open.
The function first creates a list of all possible doors (`options`) and removes the door containing the car. If the contestant has not already chosen the car door, it also removes the contestant's chosen door. The function then randomly selects one of the remaining doors to open (`door_to_open`) and returns it.
def win_car(car, contestant, monty, strategy): # Parameters # car, which is either 1, 2 or 3, represents the door behind which is a car # contestant, which is either 1, 2 or 3, represents the door that contestant chooses # monty, which is either 1, 2 or 3, represents the door that the host opens # strategy, a string which is either 'switch' or 'noswitch' # Returns # a boolean value. True for winning a car and False for winning a goat # write your code below this line。请帮我完成需要填写的代码
```python
def win_car(car, contestant, monty, strategy):
if strategy == 'noswitch':
return contestant == car
elif strategy == 'switch':
doors = [1, 2, 3]
doors.remove(monty)
doors.remove(contestant)
contestant = doors[0]
return contestant == car
else:
print('Invalid strategy!')
return None
```
这段代码首先判断 `strategy` 的值是 `'noswitch'` 还是 `'switch'`。如果是 `'noswitch'`,那么只需要判断选手最开始选择的门是否是 `car` 即可。如果是 `'switch'`,则需要先将 `monty` 打开的门从列表中删除,然后再将选手最开始选择的门也从列表中删除。此时,列表中只剩下了一扇门,即选手可以选择的另一扇门。选手可以选择这扇门,然后判断是否获得了汽车。最后,如果 `strategy` 的值既不是 `'noswitch'` 也不是 `'switch'`,那么将输出一条错误消息,并返回 `None`。
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