(Remove duplicates) Write a method that removes the duplicate elements from an array list of integers using the following header: public static void removeDuplicate(ArrayList<Integer> list) Write a test program that prompts the user to enter 10 integers to a list and displays the distinct integers in their input order and separated by exactly one space. Here is a sample run: Enter 10 integers: 34 5 3 5 6 4 33 2 2 4 The distinct integers are 34 5 3 6 4 33 2

Here's the implementation of the `removeDuplicate` method:

public static void removeDuplicate(ArrayList<Integer> list) {
    ArrayList<Integer> distinctList = new ArrayList<Integer>();
    for (Integer num : list) {
        if (!distinctList.contains(num)) {
            distinctList.add(num);
        }
    }
    list.clear();
    list.addAll(distinctList);
}

And here's the test program:

import java.util.ArrayList;
import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner input = new Scanner(System.in);
        ArrayList<Integer> list = new ArrayList<Integer>();
        System.out.print("Enter 10 integers: ");
        for (int i = 0; i < 10; i++) {
            int num = input.nextInt();
            list.add(num);
        }
        removeDuplicate(list);
        System.out.print("The distinct integers are ");
        for (Integer num : list) {
            System.out.print(num + " ");
        }
    }

    public static void removeDuplicate(ArrayList<Integer> list) {
        ArrayList<Integer> distinctList = new ArrayList<Integer>();
        for (Integer num : list) {
            if (!distinctList.contains(num)) {
                distinctList.add(num);
            }
        }
        list.clear();
        list.addAll(distinctList);
    }
}

Sample output:

Enter 10 integers: 34 5 3 5 6 4 33 2 2 4
The distinct integers are 34 5 3 6 4 33 2