利用求阶乘函数Fact()，编程计算并输出1! + 2! + …+ n!的值。 **输入格式要求："%u" 提示信息："Input n(n>0):" **输出格式要求："sum = %lu\n"

以下是代码实现：

#include <stdio.h>

unsigned long Fact(unsigned int n) {
    unsigned long result = 1;
    for(unsigned int i = 1; i <= n; i++){
        result *= i;
    }
    return result;
}

int main() {
    unsigned int n;
    printf("Input n(n>0):");
    scanf("%u", &n);
    unsigned long sum = 0;
    for(unsigned int i = 1; i <= n; i++) {
        sum += Fact(i);
    }
    printf("sum = %lu\n", sum);
    return 0;
}

运行结果示例：

Input n(n>0):5
sum = 153