Text text1 = new Text(centerX - 5, centerY - clockRadius + 12, "12"); Text text2 = new Text(centerX - clockRadius + 3, centerY + 5, "9"); Text text3 = new Text(centerX + clockRadius - 10, centerY + 3, "3"); Text text4 = new Text(centerX - 3, centerY + clockRadius - 3, "6");圆心为(150,150),得出其他的九个刻度的坐标
时间: 2024-01-27 12:05:04 浏览: 57
通过两点坐标A(x1,y1),B(x2,y2)以及半径r,求出圆心坐标
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假设时钟一共有12个刻度,包括四个已知刻度,那么可以按照以下方式计算其他8个刻度的坐标:
```
int numPoints = 12;
int angleStep = 360 / numPoints;
double[] xCoords = new double[numPoints];
double[] yCoords = new double[numPoints];
for (int i = 0; i < numPoints; i++) {
double angle = i * angleStep;
double x = centerX + clockRadius * Math.sin(Math.toRadians(angle));
double y = centerY - clockRadius * Math.cos(Math.toRadians(angle));
xCoords[i] = x;
yCoords[i] = y;
}
Text[] texts = new Text[numPoints];
texts[0] = new Text(xCoords[0] - 5, yCoords[0] - clockRadius + 12, "12");
texts[1] = new Text(xCoords[3] - clockRadius + 3, yCoords[3] + 5, "9");
texts[2] = new Text(xCoords[6] + clockRadius - 10, yCoords[6] + 3, "3");
texts[3] = new Text(xCoords[9] - 3, yCoords[9] + clockRadius - 3, "6");
for (int i = 4; i < numPoints; i++) {
double x = xCoords[i];
double y = yCoords[i];
String text = Integer.toString(i + 1);
texts[i] = new Text(x, y, text);
}
```
这段代码会创建12个刻度,其中前4个已知,后8个通过计算得到。如果需要更改刻度数量,可以调整 `numPoints` 变量的值,并相应地调整已知刻度的位置和编号。
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