请利用已给数值完成满足下列需求的java程序:private static final int NBRICKS_PER_ROW = 10; /** 每排砖的数量 */ private static final int NBRICK_ROWS = 10; /** 砖排数*/ private static final int BRICK_SEP = 4; /** 砖块之间的间隔*/ private static final int BRICK_WIDTH = /**砖的宽度 */ (WIDTH - (NBRICKS_PER_ROW - 1) * BRICK_SEP) / NBRICKS_PER_ROW; private static final int BRICK_HEIGHT = 8; /** 砖的高度*/ private static final int BRICK_Y_OFFSET = 70; /** 顶部砖排与顶部的偏移*/;请绘制上述数值下的砖块组件,通过指定坐标使得第一排砖块在窗户的中央,剩余的空间在左边和右侧。砖的颜色在两排中保持不变,并按以下顺序排列 彩虹状排列:红色、橙色、黄色、绿色、青色。
时间: 2023-08-07 08:02:07 浏览: 100
下面是一个满足需求的Java程序,可以绘制上述数值下的砖块组件:
```java
import acm.graphics.*;
import acm.program.*;
import java.awt.*;
public class RainbowBricks extends GraphicsProgram {
private static final int NBRICKS_PER_ROW = 10; //每排砖块数量
private static final int NBRICK_ROWS = 10; //砖块排数
private static final int BRICK_SEP = 4; //砖块之间的间隔
private static final int BRICK_HEIGHT = 8; //砖块的高度
private static final int BRICK_Y_OFFSET = 70; //顶部砖排与顶部的偏移
//计算砖块的宽度
private static final int BRICK_WIDTH = (WIDTH - (NBRICKS_PER_ROW - 1) * BRICK_SEP) / NBRICKS_PER_ROW;
//定义砖块颜色数组
private static final Color[] BRICK_COLORS = {Color.RED, Color.ORANGE, Color.YELLOW, Color.GREEN, Color.CYAN};
public void run() {
//计算第一个砖块的x坐标,使其位于窗口中央
int startX = (WIDTH - NBRICKS_PER_ROW * BRICK_WIDTH - (NBRICKS_PER_ROW - 1) * BRICK_SEP) / 2;
//循环绘制砖块
for (int row = 0; row < NBRICK_ROWS; row++) {
//计算砖块的y坐标
int y = BRICK_Y_OFFSET + row * (BRICK_HEIGHT + BRICK_SEP);
//循环绘制一排砖块
for (int col = 0; col < NBRICKS_PER_ROW; col++) {
//计算砖块的x坐标
int x = startX + col * (BRICK_WIDTH + BRICK_SEP);
//创建砖块
GRect brick = new GRect(x, y, BRICK_WIDTH, BRICK_HEIGHT);
//设置砖块颜色
int colorIndex = row / 2 % BRICK_COLORS.length;
brick.setFillColor(BRICK_COLORS[colorIndex]);
brick.setFilled(true);
//添加砖块到画布上
add(brick);
}
}
}
}
```
这个程序使用了循环来绘制所有的砖块,同时根据砖块的行数和列数来计算每个砖块的坐标。其中,砖块的颜色按照彩虹状排列,顺序为红色、橙色、黄色、绿色、青色。运行这个程序可以看到绘制出的彩虹状排列的砖块。
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