java求行阶梯形矩阵
时间: 2023-10-17 20:30:58 浏览: 55
以下是Java代码实现行阶梯形矩阵的方法:
```
public class RowEchelonForm {
public static void main(String[] args) {
// 3x4矩阵
double[][] matrix = {
{2, 3, 1, 5},
{4, 4, -4, 0},
{2, -3, 1, 2}
};
int rows = matrix.length;
int cols = matrix[0].length;
int lead = 0;
for (int r = 0; r < rows; r++) {
if (cols <= lead) {
break;
}
int i = r;
while (matrix[i][lead] == 0) {
i++;
if (rows == i) {
i = r;
lead++;
if (cols == lead) {
break;
}
}
}
for (int j = 0; j < cols; j++) {
double temp = matrix[r][j];
matrix[r][j] = matrix[i][j];
matrix[i][j] = temp;
}
double lv = matrix[r][lead];
for (int j = 0; j < cols; j++) {
matrix[r][j] /= lv;
}
for (int j = 0; j < rows; j++) {
if (j != r) {
double lv2 = matrix[j][lead];
for (int k = 0; k < cols; k++) {
matrix[j][k] -= lv2 * matrix[r][k];
}
}
}
lead++;
}
// 输出行阶梯形矩阵
for (int i = 0; i < rows; i++) {
for (int j = 0; j < cols; j++) {
System.out.print(matrix[i][j] + " ");
}
System.out.println();
}
}
}
```
以上代码实现的是高斯-约旦消元法,将输入矩阵转换为行阶梯形矩阵。
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