用clojure计算德州扑克胜率

以下是一个Clojure函数的示例，该函数可以计算在德州扑克中，给定手牌在公共牌未知的情况下的胜率：

(require '[combinatorics :as comb])

(defn evaluate-hand [hand board]
  ;; Evaluate the strength of a given hand with a given board
  ...)

(defn calculate-win-rate [hand]
  (let [deck (comb/cartesian-product (range 4) (range 13))
        remaining-cards (remove #(contains? (set hand) %) deck)
        all-combinations (comb/combinations remaining-cards 5)
        win-count (reduce
                    (fn [acc board]
                      (let [my-strength (evaluate-hand hand board)
                            opponent-strength (evaluate-hand (take 2 board) board)]
                        (if (> my-strength opponent-strength)
                          (inc acc)
                          acc)))
                    0
                    all-combinations)]
    (/ win-count (count all-combinations))))

此函数使用combinatorics库来生成所有可能的公共牌的组合，并对每个组合评估手牌的强度。然后，它计算手牌获胜的次数，并将其除以总次数，得到获胜的概率。