用clojure计算德州扑克6人游戏中不同手牌的 获胜概率
时间: 2024-03-19 22:43:40 浏览: 50
以下是一个Clojure程序来计算德州扑克6人游戏中不同手牌的获胜概率:
首先,我们需要定义扑克牌和所有可能的手牌:
```clojure
(def suits [:clubs :diamonds :hearts :spades])
(def values [:2 :3 :4 :5 :6 :7 :8 :9 :T :J :Q :K :A])
(def deck (for [s suits, v values]
{:suit s :value v}))
(defn combinations [n coll]
(if (<= n 0)
#{()}
(let [next (combinations (dec n) (rest coll))]
(reduce #(conj %1 (cons (first coll) %2)) next (combinations n (rest coll))))))
(defn all-hands []
(combinations 2 deck))
(defn all-boards []
(combinations 5 deck))
(defn all-possible-hands []
(combinations 2 (apply concat (repeat 6 deck)))))
```
然后,我们需要定义函数来计算给定手牌和公共牌的牌型得分:
```clojure
(defn score [cards]
(let [flush? (some #(= 5 (count (filter #(= (:suit %) %1) cards))) suits)
straight? (let [values (map :value cards)
sorted (sort > values)
straight (every? identity (map = (range (dec (count sorted))) (map - sorted (range (dec (count sorted))))))]
(or straight (and (= (take 4 sorted) [2 3 4 5]) (= (last sorted) :A))))
groups (frequencies (map :value cards))
quads (some #(= 4 (val %)) groups)
trips (some #(= 3 (val %)) groups)
pairs (filter #(= 2 (val %)) groups)]
(cond
(and flush? straight?) (+ 800 (last (sort (map :value cards))))
quads (+ 700 (last (sort (keys (select-keys groups (fn [k] (= 4 (val k))))))))
(and trips pairs) (+ 600 (last (sort (keys (select-keys groups (fn [k] (= 3 (val k))))))) (* 15 (last (sort (keys (select-keys groups (fn [k] (= 2 (val k))))))))
flush? (+ 500 (last (sort (map :value cards))))
straight? (+ 400 (last (sort (map :value cards))))
trips (+ 300 (last (sort (keys (select-keys groups (fn [k] (= 3 (val k))))))) (* 20 (last (sort (map :value cards)))))
(count pairs) 2 (+ 200 (last (sort (keys (select-keys groups (fn [k] (= 2 (val k))))))) (* 30 (last (sort (map :value cards)))))
(count pairs) 1 (+ 100 (last (sort (keys (select-keys groups (fn [k] (= 2 (val k))))))) (* 50 (last (sort (map :value cards)))))
:else (+ 50 (last (sort (map :value cards)))))))
```
接下来,我们可以定义一个函数来计算获胜概率:
```clojure
(defn win-probability [my-hand board]
(let [opponent-hands (remove #{my-hand} (all-hands))]
(loop [wins 0
ties 0
opponents opponent-hands]
(if (empty? opponents)
(/ (+ wins (* ties 0.5)) (count opponent-hands))
(let [opponent-hand (first opponents)
all-cards (concat my-hand board opponent-hand)
my-score (score (concat my-hand board))
opponent-score (score (concat opponent-hand board))]
(cond
(> my-score opponent-score) (recur (inc wins) ties (rest opponents))
(= my-score opponent-score) (recur wins (inc ties) (rest opponents))
:else (recur wins ties (rest opponents))))))))
```
最后,我们可以使用此函数来计算所有可能的手牌的获胜概率:
```clojure
(defn print-win-probabilities []
(doseq [my-hand (all-hands)]
(let [win-prob (win-probability my-hand (take 5 deck))]
(println (format "%s %s: %.4f" (my-hand 0) (my-hand 1) win-prob)))))
```
请注意,这个程序可能需要一些时间来计算所有不同手牌的获胜概率。
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