用clojure写一个德州扑克游戏
时间: 2023-12-19 08:04:07 浏览: 115
好的,下面是一个简单的德州扑克游戏的Clojure实现。这个实现只包括游戏逻辑,没有任何用户界面。
```clojure
;; 定义扑克牌的花色和点数
(def suits ["Spades" "Hearts" "Diamonds" "Clubs"])
(def ranks ["2" "3" "4" "5" "6" "7" "8" "9" "10" "Jack" "Queen" "King" "Ace"])
;; 定义一张扑克牌
(defn make-card [suit rank]
{:suit suit :rank rank})
;; 定义一副扑克牌
(defn make-deck []
(for [s suits
r ranks]
(make-card s r)))
;; 洗牌
(defn shuffle [deck]
(shuffle-seq deck))
;; 发牌
(defn deal [n players deck]
(let [hands (partition n (shuffle deck))]
(for [i (range players)]
{:player i :hand (nth hands i)})))
;; 计算牌面点数
(defn value [hand]
(let [ranks-values {"2" 2 "3" 3 "4" 4 "5" 5 "6" 6 "7" 7 "8" 8 "9" 9 "10" 10 "Jack" 11 "Queen" 12 "King" 13 "Ace" 14}]
(sort > (map ranks-values (map :rank hand)))))
;; 判断牌型
(defn hand-type [hand]
(let [values (value hand)
straight? (= (- (first values) (last values)) 4)
flush? (apply = (map :suit hand))
pairs (frequencies (map :rank hand))
has-pair? (some #(= 2 %) pairs)
has-two-pair? (and (has-pair?) (= 2 (count (filter #(= 2 %) pairs))))
has-three-of-a-kind? (some #(= 3 %) pairs)
has-four-of-a-kind? (some #(= 4 %) pairs)]
(cond
(and straight? flush?) :straight-flush
has-four-of-a-kind? :four-of-a-kind
(and has-three-of-a-kind? has-pair?) :full-house
flush? :flush
straight? :straight
has-three-of-a-kind? :three-of-a-kind
has-two-pair? :two-pair
has-pair? :pair
:else :high-card)))
;; 比较两手牌的大小
(defn compare-hands [hand1 hand2]
(let [type1 (hand-type hand1)
type2 (hand-type hand2)
value1 (value hand1)
value2 (value hand2)]
(cond
(> type1 type2) 1
(< type1 type2) -1
:else
(let [v (compare value1 value2)]
(cond
(> v 0) 1
(< v 0) -1
:else 0)))))
;; 游戏主循环
(defn main-loop []
(let [deck (make-deck)
players 3
hands (deal 2 players deck)]
(println "开始德州扑克游戏!")
(doseq [p hands]
(println (str "玩家 " (:player p) " 的手牌:" (map :rank (:hand p)))))
(let [community-cards (take 5 (drop 2 deck))
best-hand (reduce #(if (compare-hands %1 %2) %1 %2) hands)]
(doseq [c community-cards]
(println (str "公共牌:" (:rank c) " of " (:suit c))))
(println (str "最佳手牌:" (map :rank best-hand)))
(doseq [p hands]
(let [win? (= 0 (compare-hands p best-hand))]
(println (str "玩家 " (:player p) " 的手牌是 " (if win? "最佳的" "次佳的")))))))
```
这个实现只支持3个玩家,每个玩家发2张牌,然后再发5张公共牌。最后,程序会计算每个玩家的最佳牌型,并输出最佳牌型和是否胜利。你可以根据自己的需要对代码进行修改和扩展。
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