改成广度优先搜索bool dfs(int to_x, int to_y, int box_x, int box_y, int people_x, int people_y) { visit2[people_x][people_y] = 1; if (to_x == people_x && to_y == people_y) { flag1 = true; return true; } if (!flag1) { for (int i = 0; i < 4; i++) { int xx = people_x + dx[i]; int yy = people_y + dy[i]; if (xx<1 || yy<1 || xx>n || yy>m || (xx == box_x && yy == box_y) || board[xx][yy] == 1 || visit2[xx][yy]) continue; dfs(to_x, to_y, box_x, box_y, xx, yy); if (flag1) return true; } } return false; }

你想将这段代码改成广度优先搜索的形式，是吗？下面是改写后的代码：

bool bfs(int to_x, int to_y, int box_x, int box_y, int people_x, int people_y)
{
    queue<pair<int, int>> q;
    q.push({people_x, people_y});
    visit2[people_x][people_y] = 1;

    while (!q.empty())
    {
        pair<int, int> cur = q.front();
        q.pop();

        if (cur.first == to_x && cur.second == to_y)
        {
            flag1 = true;
            return true;
        }

        for (int i = 0; i < 4; i++)
        {
            int xx = cur.first + dx[i];
            int yy = cur.second + dy[i];
            if (xx < 1 || yy < 1 || xx > n || yy > m || (xx == box_x && yy == box_y) || board[xx][yy] == 1 || visit2[xx][yy])
                continue;
            q.push({xx, yy});
            visit2[xx][yy] = 1;
        }
    }

    return false;
}

这个改写后的代码使用了队列来实现广度优先搜索，每次取出队列中的一个点，然后将它周围未访问过的点加入队列。如果找到目标点，则返回true，否则返回false。注意，在每次将点加入队列之前需要将其标记为已访问。希望这个改写对你有帮助！