n=int(input()) sum=0 q=(7,9,10,5,8,4,2,1,6,3,7,9,10,5,8,4,2,1) for i in range(n): num=input() for j in num: if j=='X' or j== 'x': j=10 j=int(j) for k in q: a=j*k sum=sum+a print(sum) if sum%11!=1: n=n-1 print(n)帮我优化这段代码
时间: 2023-06-13 19:03:05 浏览: 63
这段代码存在一些语法错误和逻辑错误,我会给你修改并优化一下:
```python
n = int(input())
q = (7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2, 1)
count = 0
for i in range(n):
num = input()
s = 0
for j in num:
if j == 'X' or j == 'x':
j = 10
j = int(j)
for k in q:
s += j * k
if s % 11 == 1:
count += 1
print(count)
```
主要的优化包括:
1. 将 `sum` 改为 `s`,因为 `sum()` 是 Python 内置函数,不要使用内置函数名作为变量名。
2. 在内层循环中直接对 `s` 进行累加,不需要使用 `sum` 变量。
3. 将判断校验码是否正确的部分放到循环外部,减少重复计算。
4. 将校验码为 1 的情况计入计数器 `count` 中,最后输出 `count` 即可。
希望这个优化后的代码对你有所帮助!
相关问题
sum=0 n=int(input()) for i in range(n): sum+=1/i print(sum)
这段代码存在一个错误,因为在第i次循环中,当i等于0时,分母为0,会导致程序抛出ZeroDivisionError异常。应该从1开始循环,可以做如下修改:
```
sum = 0
n = int(input())
for i in range(1, n+1):
sum += 1/i
print(sum)
```
这样修改后,代码就可以正确地计算和了。
sum=0 m,n=int(input()) for i in range(m,n+1): sum += i print(sum)
This code appears to have syntax errors and does not perform any meaningful operation. Here is a corrected version that sums up all the integers between two given numbers:
```
m = int(input("Enter the start number: "))
n = int(input("Enter the end number: "))
sum = 0
for i in range(m, n+1):
sum += i
print("The sum of all integers between", m, "and", n, "is:", sum)
```
This code prompts the user to input the start and end numbers, initializes a sum variable to 0, and then uses a for loop to iterate over all the integers between the start and end numbers (inclusive). On each iteration, the current integer is added to the sum. Finally, the sum is printed out with a descriptive message.