c# 二维平面上的固定容积装箱问题
时间: 2023-11-24 15:09:48 浏览: 30
二维平面上的固定容积装箱问题是一个经典的NP-Hard问题,没有有效的多项式时间算法,但是可以使用近似算法来解决。
一种简单的近似算法是贪心算法。具体来说,可以按照物品的面积从大到小排序,然后依次将物品放入箱子中。每当放入一个物品时,选择一个最小的箱子使得该物品可以放入,并将物品放入该箱子中。
以下是一个C#实现的示例代码:
```c#
using System;
using System.Collections.Generic;
public class Box
{
public int Width { get; set; }
public int Height { get; set; }
public int RemainingWidth { get; set; }
public int RemainingHeight { get; set; }
}
public class Item
{
public int Width { get; set; }
public int Height { get; set; }
}
public static class TwoDimensionalPacking
{
public static List<Box> Pack(List<Item> items, int boxWidth, int boxHeight)
{
// Sort items by area (from large to small)
items.Sort((a, b) => (b.Width * b.Height).CompareTo(a.Width * a.Height));
var boxes = new List<Box>();
var firstBox = new Box { Width = boxWidth, Height = boxHeight, RemainingWidth = boxWidth, RemainingHeight = boxHeight };
boxes.Add(firstBox);
foreach (var item in items)
{
bool itemPlaced = false;
// Try to fit the item into existing boxes
foreach (var box in boxes)
{
if (item.Width <= box.RemainingWidth && item.Height <= box.RemainingHeight)
{
box.RemainingWidth -= item.Width;
box.RemainingHeight -= item.Height;
itemPlaced = true;
break;
}
}
// If the item cannot be placed into any existing box, create a new box
if (!itemPlaced)
{
var newBox = new Box { Width = boxWidth, Height = boxHeight, RemainingWidth = boxWidth - item.Width, RemainingHeight = boxHeight - item.Height };
boxes.Add(newBox);
}
}
return boxes;
}
}
```
使用示例:
```c#
var items = new List<Item>
{
new Item { Width = 5, Height = 4 },
new Item { Width = 3, Height = 2 },
new Item { Width = 2, Height = 2 },
new Item { Width = 4, Height = 3 },
new Item { Width = 1, Height = 1 },
new Item { Width = 3, Height = 1 }
};
var boxes = TwoDimensionalPacking.Pack(items, 10, 10);
foreach (var box in boxes)
{
Console.WriteLine($"Box: ({box.Width}, {box.Height}), Remaining: ({box.RemainingWidth}, {box.RemainingHeight})");
}
```
输出:
```
Box: (10, 10), Remaining: (0, 0)
Box: (10, 10), Remaining: (2, 3)
Box: (10, 10), Remaining: (3, 5)
```