unity实现贴图矩阵运算（旋转平移缩放）

unity实现贴图矩阵运算（旋转平移缩放）实现贴图矩阵运算（旋转平移缩放）

主要为大家详细介绍了unity实现贴图矩阵运算，旋转平移缩放，文中示例代码介绍的非常详细，具有一定的参

考价值，感兴趣的小伙伴们可以参考一下

我们在shader中对贴图处理时，有时候会有一些比较复杂的运算，比方说三角函数，开方等，一般情况下，如果可以在越上

层做运算，性能会越高。C# > Vertex > fragment

因此，考虑到贴图的旋转用到的三角函数，可以使用在C#中传入旋转矩阵得到，然后使用uv直接乘以矩阵就可以了。

封装了vmatrix4x4，分享一下：

using UnityEngine;

public VMatrix()

{

m = new float[4, 4];

m[0, 0] = 0.0f; m[0, 1] = 0.0f; m[0, 2] = 0.0f; m[0, 3] = 0.0f;

m[1, 0] = 0.0f; m[1, 1] = 0.0f; m[1, 2] = 0.0f; m[1, 3] = 0.0f;

m[2, 0] = 0.0f; m[2, 1] = 0.0f; m[2, 2] = 0.0f; m[2, 3] = 0.0f;

m[3, 0] = 0.0f; m[3, 1] = 0.0f; m[3, 2] = 0.0f; m[3, 3] = 0.0f;

}

}

public static void MatrixBuildTranslation(VMatrix matrix, float x, float y, float z)

{

MatrixSetIdentity(matrix);

matrix.m[0,3] = x;

matrix.m[1,3] = y;

matrix.m[2,3] = z;

}

}

public static void MatrixBuildScale(VMatrix matrix, float x, float y, float z)

{

matrix.m[0, 0] = x; matrix.m[0, 1] = 0.0f; matrix.m[0, 2] = 0.0f; matrix.m[0, 3] = 0.0f;

matrix.m[1, 0] = 0.0f; matrix.m[1, 1] = y; matrix.m[1, 2] = 0.0f; matrix.m[1, 3] = 0.0f;

matrix.m[2, 0] = 0.0f; matrix.m[2, 1] = 0.0f; matrix.m[2, 2] = z; matrix.m[2, 3] = 0.0f;

matrix.m[3, 0] = 0.0f; matrix.m[3, 1] = 0.0f; matrix.m[3, 2] = 0.0f; matrix.m[3, 3] = 1.0f;

}

{

float radians = angleDegrees * (Mathf.PI / 180.0f);

float fSin = Mathf.Sin(radians);

float fCos = Mathf.Cos(radians);

matrix.m[0, 0] = fCos; matrix.m[0, 1] = -fSin; matrix.m[0, 2] = 0.0f; matrix.m[0, 3] = 0.0f;

matrix.m[1, 0] = fSin; matrix.m[1, 1] = fCos; matrix.m[1, 2] = 0.0f; matrix.m[1, 3] = 0.0f;

matrix.m[2, 0] = 0.0f; matrix.m[2, 1] = 0.0f; matrix.m[2, 2] = 1.0f; matrix.m[2, 3] = 0.0f;

matrix.m[3, 0] = 0.0f; matrix.m[3, 1] = 0.0f; matrix.m[3, 2] = 0.0f; matrix.m[3, 3] = 1.0f;

}