always @ (posedge clk or posedge rst) begin if (rst) begin seg = 4'b0000; end else Error (10170): Verilog HDL syntax error at keshe11.v(84) near text "always"; expecting ";", or "@", or "end", or an identifier ("always" is a reserved keyword ), or a system task, or "{", or a sequential statement这个错误怎么改

这个错误是因为 always 语句中的语法有问题。你需要在 always 后面添加 @(*) 或者 @ (posedge clk) 来指定触发条件。

例如：

always @(*) begin
    if (rst) begin
        seg = 4'b0000;
    end else begin
        // your code here
    end
end

或者

always @(posedge clk) begin
    if (rst) begin
        seg = 4'b0000;
    end else begin
        // your code here
    end
end

注意：以上代码只是示例，你需要将其中的代码替换成你自己的代码。同时，还需要确保你的代码没有其他的语法错误。

相关问题

module seg_decode( input wire clk, input wire rst_n, input wire [4:0] seg_value_1, input wire [4:0] seg_value_2, output reg [5:0] sel, output reg [7:0] seg ); parameter CNT_20US = 10'd999; reg [3:0] number; wire [2:0] change_l; wire [2:0] change_h; reg [9:0] cnt; //计时模块 always@(posedge clk or negedge rst_n)begin if(!rst_n)begin cnt <= 10'd0; end else if(cnt == CNT_20US)begin cnt <= 10'd0; end else begin cnt <= cnt + 10'd1; end end always @(posedge clk or negedge rst_n) begin if(!rst_n)begin sel <= 6'b011111; end else if(cnt == CNT_20US)begin sel <= {sel[0],sel[5:1]}; end else begin sel <= sel; end end always @(posedge clk or negedge rst_n) begin if(!rst_n)begin number <= 4'd0; end else begin case(sel) 6'b011111: number <= seg_value_1 % 10; 6'b101111: number <= seg_value_1 / 10; 6'b110111: number <= seg_value_2 % 10; 6'b111011: number <= seg_value_2 / 10; 6'b111101: begin if(seg_value_2 < seg_value_1) number <= 4'd15; else number <= change_l; end 6'b111110: begin if(seg_value_2 < seg_value_1) number <= 4'd14; else number <= change_h; end default:number <= 4'd0; endcase end end always @(posedge clk or negedge rst_n) begin if(!rst_n)begin seg <= 8'b1100_0000; end else begin case(number) 4'd0: seg <= 8'b1100_0000; 4'd1: seg <= 8'b1111_1001; 4'd2: seg <= 8'b1010_0100; 4'd3: seg <= 8'b1011_0000; 4'd4: seg <= 8'b1001_1001; 4'd5: seg <= 8'b1001_0010; 4'd14: seg <= 8'b1000_0110; 4'd15: seg <= 8'b1100_1110; default:seg <= 8'b1100_0000; endcase end end assign change_l = (seg_value_2 - seg_value_1) % 10; assign change_h = (seg_value_2 - seg_value_1) / 10; sel_drive sel_drive_u ( .clk (clk), .rst_n (rst_n), .sel_2 () ); endmodule

这段代码是一个用 Verilog HDL 编写的七段数码管驱动模块。它包括计时模块、数码管位选模块和数码管段选模块。其中，计时模块用于产生定时信号，数码管位选模块用于控制数码管位选信号，数码管段选模块用于根据输入的数值控制数码管的显示。这个模块包括了一些输入输出端口，比如时钟信号 clk、复位信号 rst_n、两个输入数值 seg_value_1 和 seg_value_2，以及两个输出信号 sel 和 seg。

always @ (posedge clk ) begin if (rst) begin seg = 4'b0000; end Error (10170): Verilog HDL syntax error at keshe11.v(84) near text "always"; expecting ";", or "@", or "end", or an identifier ("always" is a reserved keyword ), or a system task, or "{", or a sequential statement错误怎么改

这个错误提示是因为 always 前面缺少了一个语句块的括号，应该在 always 后面添加一个 begin/end 语句块，像这样：

always @(posedge clk) begin
    if (rst) begin
        seg = 4'b0000;
    end
end

这样就可以消除这个错误了。