always @ (posedge clk) begin if (rst) begin seg <= 4'b1111; an <= 3'b111; scan_counter <= 0; password_index <= 0; current_digit <= 4'b0000; is_locked <= 0; show_password <= 0; for (int i = 0; i < password_length; i = i + 1) begin password[i] <= 4'b0000; end end else begin // 数码管扫描 存在Error (10170): Verilog HDL syntax error at password1.v(32) near text ")"; expecting ";"这个错误怎么改，改完之后的代码

这个错误提示是因为 `for` 循环语句后面需要加上分号 `;`，你可以将代码修改为：

always @ (posedge clk) begin
    if (rst) begin
        seg <= 4'b1111;
        an <= 3'b111;
        scan_counter <= 0;
        password_index <= 0;
        current_digit <= 4'b0000;
        is_locked <= 0;
        show_password <= 0;
        for (int i = 0; i < password_length; i = i + 1) begin
            password[i] <= 4'b0000;
        end
    end else begin
        // 数码管扫描
        for (int i = 0; i < 4; i = i + 1) begin
            case (i)
                0: seg <= password[current_digit + 3];
                1: seg <= password[current_digit + 2];
                2: seg <= password[current_digit + 1];
                3: seg <= password[current_digit];
            endcase
            case (scan_counter)
                0: an <= 3'b111;
                1: an <= 3'b110;
                2: an <= 3'b101;
                3: an <= 3'b011;
            endcase
            current_digit <= current_digit + 1;
            if (current_digit >= password_length) begin
                current_digit <= 4'b0000;
            end
        end
        // 密码验证
        if (keypad_data_valid) begin
            if (password[password_index] == keypad_data) begin
                password_index <= password_index + 1;
                if (password_index >= password_length) begin
                    is_locked <= 0;
                end
            end else begin
                password_index <= 0;
                is_locked <= 1;
            end
            keypad_data_valid <= 0;
        end
        // 显示密码
        if (show_password) begin
            seg <= password[password_index];
            case (scan_counter)
                0: an <= 3'b111;
                1: an <= 3'b110;
                2: an <= 3'b101;
                3: an <= 3'b011;
            endcase
        end
        // 数码管扫描计数器
        scan_counter <= scan_counter + 1;
        if (scan_counter >= 4) begin
            scan_counter <= 0;
        end
    end
end

这样就可以消除该错误。