java求行阶梯形矩阵
时间: 2023-10-17 18:30:58 浏览: 42
以下是 Java 实现的行阶梯形矩阵:
```java
public class RowEchelonMatrix {
public static void main(String[] args) {
int[][] matrix = {{2, 1, -1, 8}, {-3, -1, 2, -11}, {-2, 1, 2, -3}};
int numRows = matrix.length;
int numCols = matrix[0].length;
int lead = 0;
for (int r = 0; r < numRows; r++) {
if (lead >= numCols) {
break;
}
int i = r;
while (matrix[i][lead] == 0) {
i++;
if (i == numRows) {
i = r;
lead++;
if (lead == numCols) {
break;
}
}
}
int[] temp = matrix[r];
matrix[r] = matrix[i];
matrix[i] = temp;
int lv = matrix[r][lead];
for (int j = 0; j < numCols; j++) {
matrix[r][j] /= lv;
}
for (int i2 = 0; i2 < numRows; i2++) {
if (i2 != r) {
int lv2 = matrix[i2][lead];
for (int j = 0; j < numCols; j++) {
matrix[i2][j] -= lv2 * matrix[r][j];
}
}
}
lead++;
}
for (int i = 0; i < numRows; i++) {
for (int j = 0; j < numCols; j++) {
System.out.print(matrix[i][j] + " ");
}
System.out.println();
}
}
}
```
该程序可以将矩阵转化为行阶梯形矩阵形式,并输出结果。