代码 基于产线产能限制的 多条产线 生产 多种产品和半成品 且考虑半成品初始库存量 将月度成品和半成品需求拆分到每天，满足切换产线次数少

算法思路：

1. 定义每个产品和半成品的产能需求和初始库存量。

2. 将月度需求拆分为每天的需求量。

3. 针对每天的需求，按照优先级选择最优的产线进行生产，并更新库存量。

4. 如果某个产品或半成品的库存量不足以满足当天的需求，则需要先生产满足库存不足的产线，再选择其他产线满足需求。

5. 在满足当天需求的同时，尽可能减少切换产线的次数。

6. 重复执行第3到第5步，直到所有需求都得到了满足。

代码实现：

class Product:
    def __init__(self, name, capacity, inventory):
        self.name = name
        self.capacity = capacity
        self.inventory = inventory

class DailyDemand:
    def __init__(self, date, demand):
        self.date = date
        self.demand = demand

class ProductionLine:
    def __init__(self, name, capacity, products):
        self.name = name
        self.capacity = capacity
        self.products = products

    def can_produce(self, product, demand):
        return self.capacity >= product.capacity * demand

def get_production_plan(products, production_lines, daily_demands):
    production_plan = []
    for daily_demand in daily_demands:
        demands = [(product, daily_demand.demand) for product in products]
        while demands:
            best_line = None
            best_product = None
            best_demand = 0
            for product, demand in demands:
                for line in production_lines:
                    if line.can_produce(product, demand):
                        if best_line is None or line.capacity > best_line.capacity:
                            best_line = line
                            best_product = product
                            best_demand = demand
            if best_line is None:
                # no line can produce any of the remaining products
                break
            production_plan.append((daily_demand.date, best_line, best_product, best_demand))
            best_line.capacity -= best_product.capacity * best_demand
            demands.remove((best_product, best_demand))
    return production_plan

# example usage
if __name__ == "__main__":
    p1 = Product("A", 10, 20)
    p2 = Product("B", 5, 10)
    p3 = Product("C", 2, 5)
    products = [p1, p2, p3]

    pl1 = ProductionLine("Line 1", 20, [p1, p2])
    pl2 = ProductionLine("Line 2", 15, [p2, p3])
    production_lines = [pl1, pl2]

    daily_demands = [
        DailyDemand("2022-01-01", {p1: 50, p2: 30, p3: 10}),
        DailyDemand("2022-01-02", {p1: 40, p2: 20, p3: 15}),
        DailyDemand("2022-01-03", {p1: 60, p2: 40, p3: 20}),
    ]

    production_plan = get_production_plan(products, production_lines, daily_demands)

    for date, line, product, demand in production_plan:
        print(f"{date}: {line.name} produces {product.name} x {demand}")