利用链表实现多项式加法运算,并计算多项式p1(x)和p2(x)相加的结果。 p1(x) = 7+3x+9x^8+5x^17, p2(x) = 8x+22x^7-9x^8
时间: 2024-10-08 14:24:14 浏览: 60
要使用链表实现多项式加法运算,我们可以创建一个节点结构,每个节点包含系数和指数。对于给定的两个多项式p1(x)和p2(x),我们需要遍历两个链表,分别对应p1和p2的每一项,然后根据指数相加规则(相同指数项相加)更新节点的系数。
首先,定义一个节点结构`Node`:
```c
typedef struct {
int coefficient;
int exponent; // 或者用long long避免溢出
struct Node* next;
} PolynomialTerm;
```
接下来,创建两个链表表示p1和p2:
```c
PolynomialTerm* p1_head = NULL;
PolynomialTerm* p2_head = NULL;
// 初始化p1链表,添加每一项
PolynomialTerm* p1_current = malloc(sizeof(PolynomialTerm));
p1_current->coefficient = 7;
p1_current->exponent = 0;
p1_current->next = NULL;
if (p1_head == NULL) {
p1_head = p1_current;
}
// 添加p2链表,同样初始化每一项
PolynomialTerm* p2_current = malloc(sizeof(PolynomialTerm));
p2_current->coefficient = 8;
p2_current->exponent = 1;
p2_current->next = NULL;
if (p2_head == NULL) {
p2_head = p2_current;
}
// 假设还有其他p2的项,按照同样的方式添加
// 进行加法操作
PolynomialTerm* result_head = NULL;
PolynomialTerm* result_current = NULL;
for (PolynomialTerm* current = p1_head; current != NULL; current = current->next) {
for (PolynomialTerm* other = p2_head; other != NULL; other = other->next) {
if (current->exponent == other->exponent) {
// 同一项,合并系数
current->coefficient += other->coefficient;
// 如果合并后系数为0,说明不需要保留该项
if (current->coefficient == 0) {
free(current);
current = NULL;
} else {
break;
}
} else if (current->exponent < other->exponent) {
// 结果链表上没有相同或更小指数的项,插入当前项
if (result_head == NULL) {
result_head = current;
result_current = current;
} else {
result_current->next = current;
result_current = current;
}
}
}
// 如果p1还没有处理完,将其剩余项添加到结果链表
if (current != NULL) {
result_head = current;
result_current = current;
}
}
// 清理p2链表(如果不需要)
free(p2_current);
while (p2_head != NULL) {
PolynomialTerm* temp = p2_head;
p2_head = p2_head->next;
free(temp);
}
return result_head;
```
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