c循环对于给定的正整数N，需要你计算 S=1!+2!+3!+...+N！

以下是计算S=1!+2!+3!+...+N!并判断S中是否含N的C语言代码：

#include <stdio.h>

int main() {
    int n, i, j, s = 0, flag = 0;
    scanf("%d", &n);
    for (i = 1; i <= n; i++) {
        int factorial = 1;
        for (j = 1; j <= i; j++) {
            factorial *= j;
        }
        s += factorial;
    }
    while (s > 0) {
        if (s % 10 == n) {
            flag = 1;
            break;
        }
        s /= 10;
    }
    if (flag == 1) {
        printf("1\n");
    } else {
        printf("0\n");
    }
    return 0;
}