输入n,求1!+2!+3!+4!+…+n!C++

以下是C++求1!+2!+3!+4!+…+n!的代码：

#include <iostream>
using namespace std;

int main() {
    int n;
    int sum = 0, team = 1;
    cout << "请输入n的值：";
    cin >> n;
    if (n <= 0) {
        cout << "n为正整数，请重新输入" << endl;
        return 0;
    }
    for (int i = 1; i <= n; i++) {
        team *= i;
        sum += team;
    }
    cout << "该式的值为：" << sum << endl;
    return 0;
}

相关问题

输入n,求1!+2!+3!+4!+…+n!单循环实现C++

以下是单循环实现输入n,求1!+2!+3!+4!+…+n!的C++代码：

#include <iostream>
using namespace std;

int main() {
    int n;
    int sum = 0;
    int m = 1;
    cout << "请输入n的值：";
    cin >> n;
    for (int i = 1; i <= n; i++) {
        m *= i;
        sum += m;
    }
    cout << "1!+2!+3!+4!+…+n!的和为：" << sum << endl;
    return 0;
}

输入n,求1!+2!+3!+4!+…+n!循环的嵌套C++

以下是输入n，求1!+2!+3!+4!+…+n!循环的嵌套C++代码：

#include <iostream>
using namespace std;

int main() {
    int n;
    int sum = 0;
    int team = 1;
    cout << "请输入n的值：";
    cin >> n;
    if (n <= 0) {
        cout << "n为正整数，请重新输入" << endl;
        return 0;
    }
    for (int i = 1; i <= n; i++) {
        team = 1;
        for (int j = 1; j <= i; j++) {
            team *= j;
        }
        sum += team;
    }
    cout << "该式的值为：" << sum << endl;
    return 0;
}