求1!+2!+3!+4!+5!+…+n!的和cpp

以下是求1!+2!+3!+4!+5!+…+n!的和的C++代码：

#include <iostream>
using namespace std;

int main() {
    int n;
    int sum = 0, team = 1;
    cout << "请输入n的值：";
    cin >> n;
    if (n <= 0) {
        cout << "n为正整数，请重新输入" << endl;
        return 0;
    }
    for (int i = 1; i <= n; i++) {
        team *= i;
        sum += team;
    }
    cout << "该式的值为：" << sum << endl;
    return 0;
}

相关问题

求1!+2!+3!+4!+5!+…+n!的和 cpp

以下是两种C++求1!+2!+3!+4!+5!+…+n!的和的例子：

1.使用for循环计算阶乘和

#include<iostream>
using namespace std;
int main()
{
    int n;
    unsigned long long m = 1;
    unsigned long long z = 0;
    cout << "请输入n的值:";
    cin >> n;
    for (int i = 1; i <= n; i++)
    {
        m *= i;
        z += m;
    }
    cout << "1!+2!+3!+...+" << n << "!的和为：" << z << endl;    return 0;
}

2.使用嵌套for循环计算阶乘和

#include<stdio.h>
int main()
{
    int i, j, n;
    int sum = 0;
    int team = 1;
    printf("请输入n的值:");
    scanf("%d", &n);
    if (n <= 0)
    {
        printf("n为正整数，请重新输入\n");
    }
    for (i = 1; i <= n; i++)
    {
        for (j = 1; j <= i; j++)
        {
            team = team * j;
        }
        sum = team + sum;
        team = 1;
    }
    printf("1!+2!+3!+...+%d!的和为：%d", n, sum);
    return 0;
}

vs求1！+2！+3！+4！+5！+6！+7！+8！+9！+10！

你好！求1！+2！+3！+4！+5！+6！+7！+8！+9！+10！可以通过循环来实现。首先，我们需要知道阶乘的计算方法。阶乘是指从1乘到给定的数的连乘积。例如，5的阶乘表示为5!，计算方法为5 × 4 × 3 × 2 × 1 = 120。

下面是求解1！+2！+3！+4！+5！+6！+7！+8！+9！+10！的代码：

#include <iostream>

int factorial(int n) {
    int result = 1;
    for (int i = 1; i <= n; ++i) {
        result *= i;
    }
    return result;
}

int main() {
    int sum = 0;
    for (int i = 1; i <= 10; ++i) {
        sum += factorial(i);
    }
    std::cout << "1! + 2! + 3! + 4! + 5! + 6! + 7! + 8! + 9! + 10! = " << sum << std::endl;

    return 0;
}

运行以上代码，将得到结果：1! + 2! + 3! + 4! + 5! + 6! + 7! + 8! + 9! + 10! = 4037913。