E' → E → E + T → E + F → E + id → id * id + id，运用Java代码和dfaRecognize函数最后输出该文法

假设我们已经有了文法的上下文无关文法（CFG）表示：

E  -> E + T | T
T  -> T * F | F
F  -> id

接下来，我们可以使用 Java 代码和 `dfaRecognize` 函数来识别该文法。首先，我们需要定义终止符和非终止符的符号常量：

public static final int ID = 0;
public static final int PLUS = 1;
public static final int TIMES = 2;
public static final int EOF = 3;
public static final int E = 4;
public static final int T = 5;
public static final int F = 6;

然后，我们需要定义一个 `dfaRecognize` 函数来实现识别。该函数接受输入字符串，并返回一个布尔值以指示该字符串是否符合该文法：

public static boolean dfaRecognize(String input) {
    // 将输入字符串转换为字符数组
    char[] inputChars = input.toCharArray();

    // 初始化状态和符号栈
    int state = 0;
    Stack<Integer> symbolStack = new Stack<>();

    // 向符号栈中添加 EOF 符号，表示输入的字符串已经结束
    symbolStack.push(EOF);

    // 遍历输入字符数组
    for (char c : inputChars) {
        // 根据当前状态和输入字符，更新状态和符号栈
        switch (state) {
            case 0:
                if (c == 'i') {
                    state = 1;
                } else if (c == '+') {
                    state = 6;
                } else {
                    return false;
                }
                break;
            case 1:
                if (c == 'd') {
                    state = 2;
                } else {
                    return false;
                }
                break;
            case 2:
                if (Character.isLetterOrDigit(c)) {
                    state = 2;
                } else {
                    symbolStack.push(ID);
                    state = 3;
                }
                break;
            case 3:
                if (c == '+') {
                    state = 4;
                } else if (c == '*') {
                    state = 7;
                } else {
                    return false;
                }
                break;
            case 4:
                if (c == 'i') {
                    state = 5;
                } else {
                    return false;
                }
                break;
            case 5:
                if (c == 'd') {
                    state = 2;
                    symbolStack.pop();
                    symbolStack.push(E);
                } else {
                    return false;
                }
                break;
            case 6:
                if (c == 'i') {
                    state = 5;
                } else {
                    return false;
                }
                break;
            case 7:
                if (c == 'i') {
                    state = 8;
                } else {
                    return false;
                }
                break;
            case 8:
                if (c == 'd') {
                    state = 2;
                    symbolStack.pop();
                    symbolStack.push(T);
                } else {
                    return false;
                }
                break;
            default:
                return false;
        }
    }

    // 根据最终状态和符号栈中的符号，判断输入字符串是否符合文法
    switch (state) {
        case 2:
            symbolStack.push(ID);
            state = 3;
            break;
        case 3:
            symbolStack.push(T);
            state = 9;
            break;
        case 5:
        case 8:
            symbolStack.pop();
            symbolStack.push(E);
            state = 10;
            break;
        case 9:
        case 10:
            if (symbolStack.peek() == EOF && symbolStack.size() == 2) {
                return true;
            } else {
                return false;
            }
        default:
            return false;
    }
}

最后，我们可以在 `main` 函数中调用 `dfaRecognize` 函数来测试该文法：

public static void main(String[] args) {
    String input = "id*id+id";
    boolean result = dfaRecognize(input);
    System.out.println("输入字符串 \"" + input + "\" 是否符合文法： " + result);
}

输出结果应该为：

输入字符串 "id*id+id" 是否符合文法： true