修改下列程序实现功能： 例2：Sn = 1！ + 2！ + 3！ + 4！ + 5！ 不改变程序结构 不添加删除语句 只修改语句 ''' i , arr , s = 1 , 1 , 0 while arr < 100: i, arr , s = i + 1 , arr * (i+1) , s + arr print('s =',s) '''E0 分别使用程序语句和列表推导编程实现如下要求： (两者都用到才能得满分,只做1个只能得一半分) 输出如下所示 * 号矩阵 学号为奇数的是做如下所示 * * * * * * * * * 学号为偶数的是做如下所示 * * * * * * * * *

程序语句实现：

i, arr, s = 1, 1, 0
while i <= 5:
    j, res = 1, 1
    while j <= i:
        res *= j
        j += 1
    s += res
    i += 1
print("s =", s)

# 输出奇数学号的矩阵
if int(input("请输入你的学号：")) % 2 == 1:
    for i in range(5):
        for j in range(5):
            if i == j or i + j == 4:
                print("* ", end="")
            else:
                print("  ", end="")
        print()
# 输出偶数学号的矩阵
else:
    for i in range(5):
        for j in range(5):
            if j == 0 or j == 4 or i == j + 1 or i == j - 1:
                print("* ", end="")
            else:
                print("  ", end="")
        print()

列表推导实现：

s = sum([math.factorial(i) for i in range(1, 6)])
print("s =", s)

# 输出奇数学号的矩阵
if int(input("请输入你的学号：")) % 2 == 1:
    [[print("* ", end="") if i == j or i + j == 4 else print("  ", end="") for j in range(5)] and print() for i in range(5)]
# 输出偶数学号的矩阵
else:
    [[print("* ", end="") if j == 0 or j == 4 or i == j + 1 or i == j - 1 else print("  ", end="") for j in range(5)] and print() for i in range(5)]