计算1!+2!+3!+……+15!

以下是计算1!+2!+3!+……+15!的Python代码：

sum = 0
factorial = 1
for i in range(1, 16):
    factorial *= i
    sum += factorial
print(sum)

这段代码使用了for循环和累加器的方法，每次循环计算出当前数的阶乘并加到累加器中，最后输出累加器的值即可得到结果。

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3、计算1!+2!+3!+……+15!

#include<stdio.h>
int main() {
int i = 0;
int set = 1;
int n = 0;
int sum = 0;
for (n = 1; n <= 15; n++) {
for (i = 1; i <= n; i++) {
set = set * i;
}
sum = sum + set;
set = 1; //每次循环结束后需要将set重新赋值为1
}
printf("%d\n", sum);
return 0;
}

1、计算1!+2!+3!+……+15!要求详细过程

首先，我们需要明确阶乘的定义：n! = n × (n-1) × (n-2) × … × 3 × 2 × 1。

现在我们可以开始计算1! 2! 3! …… 15!，按照顺序逐个计算每个数的阶乘。

1! = 1

2! = 2 × 1 = 2

3! = 3 × 2 × 1 = 6

4! = 4 × 3 × 2 × 1 = 24

5! = 5 × 4 × 3 × 2 × 1 = 120

6! = 6 × 5 × 4 × 3 × 2 × 1 = 720

7! = 7 × 6 × 5 × 4 × 3 × 2 × 1 = 5,040

8! = 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 = 40,320

9! = 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 = 362,880

10! = 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 = 3,628,800

11! = 11 × 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 = 39,916,800

12! = 12 × 11 × 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 = 479,001,600

13! = 13 × 12 × 11 × 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 = 6,227,020,800

14! = 14 × 13 × 12 × 11 × 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 = 87,178,291,200

15! = 15 × 14 × 13 × 12 × 11 × 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 = 1,307,674,368,000

因此，1! 2! 3! …… 15! 的计算结果为：

1, 2, 6, 24, 120, 720, 5,040, 40,320, 362,880, 3,628,800, 39,916,800, 479,001,600, 6,227,020,800, 87,178,291,200, 1,307,674,368,000。