把MATLAB代码[qq,ll] = eig(A, M); [rho,ii] = min(diag(ll)); delta = qq(2,ii)/qq(1,ii);转换成Fortran代码

以下是将MATLAB代码转换成Fortran代码的方式：

! Declarations
REAL, DIMENSION(:,:), ALLOCATABLE :: qq, ll, A, M
REAL, DIMENSION(:), ALLOCATABLE :: diag
INTEGER :: ii
REAL :: rho, delta

! Allocate memory for arrays A and M
ALLOCATE(A(n,n), M(n,n))

! Assign values to arrays A and M

! Call eig function
CALL EIG(A, M, ll, qq)

! Find minimum diagonal element and its index
diag = DIAGONAL(ll)
ii = MINLOC(diag)

! Compute rho and delta
rho = diag(ii)
delta = qq(2,ii) / qq(1,ii)

! Deallocate memory
DEALLOCATE(A, M, ll, qq, diag)

请注意，Fortran中的数组索引从1开始，而不是从0开始。因此，在MATLAB代码中的所有索引都需要加1。

相关问题

[qq,ll] = eig([x p]’*[v A*p],[x p]’*[u M*p]); [rho,ii] = min(diag(ll)); delta = qq(2,ii)/qq(1,ii);举个例子

这段代码是在MATLAB中使用特征值分解（eig）函数对矩阵[x p]'*[v A*p]和[x p]'*[u M*p]进行分解。分解后得到的特征向量存储在qq中，特征值存储在ll中。接下来，通过min函数找到ll的对角线元素中的最小值和对应的索引ii。最后，计算delta值，即qq(2,ii)/qq(1,ii)。

! DeclarationsREAL, DIMENSION(:,:), ALLOCATABLE :: qq, ll, A, MREAL, DIMENSION(:), ALLOCATABLE :: diagINTEGER :: iiREAL :: rho, delta! Allocate memory for arrays A and MALLOCATE(A(n,n), M(n,n))! Assign values to arrays A and M! Call eig functionCALL EIG(A, M, ll, qq)! Find minimum diagonal element and its indexdiag = DIAGONAL(ll)ii = MINLOC(diag)! Compute rho and deltarho = diag(ii)delta = qq(2,ii) / qq(1,ii)! Deallocate memoryDEALLOCATE(A, M, ll, qq, diag)；rho，ii，delta是矩阵还是数字

rho, ii, and delta are numbers. The code is allocating memory for arrays A, M, ll, and qq, and then performing some calculations using these arrays. Finally, it deallocates the memory for these arrays.