详细解释一下这段话The direct summation causes that the response maximum of the feature group is positively related to the number of fea- tures in the group. Next, the summation is normalized to relieve this relativity
时间: 2024-03-04 12:52:51 浏览: 19
这段话是在讨论特征组的响应最大值与组中特征数量之间的关系。其中,“direct summation”指的是直接将特征组中各个特征的值相加得到的结果,这种方法会导致特征组的响应最大值与组中特征数量呈正相关关系,也就是说,特征数量越多,响应最大值就越大。
为了消除这种相关性,需要对求和结果进行归一化处理。归一化可以将求和结果映射到一个固定的范围内,比如[0,1],这样就可以消除特征数量对响应最大值的影响。具体而言,归一化可以通过Z-score标准化、最小-最大规范化等方法实现,其中最小-最大规范化是将所有特征值线性映射到[0,1]区间内,公式为:(x-min)/(max-min)。
因此,这段话的意思是:通过直接求和得到的特征组响应最大值与组中特征数量呈正相关关系,为了消除这种相关性,需要对求和结果进行归一化处理。
相关问题
Write a program in C to calculate the sum of numbers from 1 to n using recursion. Input: Input a positve integer n. Output : Compute the summation of 1+2+...+n. Sample of Input: 5 Sample of Output: 15
Sure, I can help you with that. Here's the C program to calculate the sum of numbers from 1 to n using recursion:
```c
#include <stdio.h>
int sum(int n);
int main() {
int n, result;
printf("Enter a positive integer: ");
scanf("%d", &n);
result = sum(n);
printf("The sum of numbers from 1 to %d is %d.\n", n, result);
return 0;
}
int sum(int n) {
if (n == 0) {
return 0;
} else {
return n + sum(n-1);
}
}
```
Explanation:
The program takes a positive integer `n` as input from the user and calls the `sum()` function with `n` as argument.
The `sum()` function is a recursive function that takes an integer `n` as input and returns the sum of numbers from 1 to `n`.
If `n` is 0, the function returns 0. Otherwise, it adds `n` to the sum of numbers from 1 to `n-1` by calling itself recursively with `n-1` as argument.
Finally, the program outputs the result, which is the sum of numbers from 1 to `n`.
) Please write a recursive method that sums all the numbers in a given integer and returns the summation. Only recursive solutions will be marked. [12%] // Input : 178 // Output : 1*7*8 = 56 public static int multiplication(int number){ //Fill in the method body. }
Here's a recursive method in Java that sums all the digits of a given integer:
```java
public static int sumDigits(int number) {
if (number == 0) {
return 0;
} else {
return (number % 10) + sumDigits(number / 10);
}
}
```
Here's how it works:
1. The method takes an integer `number` as input.
2. If `number` is zero, the method returns zero (this is the base case).
3. Otherwise, the method returns the sum of the last digit of `number` (which is `number % 10`) and the result of calling itself recursively with the remaining digits (which is `sumDigits(number / 10)`).
For example, if we call `sumDigits(178)`, the method will compute `8 + sumDigits(17)`, which in turn will compute `7 + sumDigits(1)`, which finally returns `1`. So the overall result is `8 + 7 + 1 = 16`.
Note that this method doesn't use multiplication as in the example in the prompt. Instead, it sums the digits of the input number recursively.
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