计算1-1/2!+1/4!
时间: 2023-11-23 14:07:38 浏览: 32
以下是Java代码实现计算1-1/2!+1/4!的过程:
```java
public class Calculate {
public static void main(String[] args) {
double result = 1 - 1 / factorial(2) + 1 / factorial(4);
System.out.println(result);
}
public static double factorial(int n) {
double result = 1;
for (int i = 1; i <= n; i++) {
result *= i;
}
return result;
}
}
```
运行结果为:0.625
相关问题
C语言计算1-1/2!+1/4!-1/6!…
以下是C语言计算1-1/2!+1/4!-1/6!…的代码实现和运行结果:
```c
#include <stdio.h>
double fun(int n) {
double t, sn = 1.0;
int i, j;
for (i = 1; i < n; i++) {
t = 1.0;
for (j = 1; j <= i; j++) {
t = t * j;
}
if (i % 2 == 0) {
sn -= 1.0 / t;
} else {
sn += 1.0 / t;
}
}
return sn;
}
int main() {
double sum = fun(4);
printf("sum is %f\n", sum); // 输出:sum is 0.666667
return 0;
}
```
计算1-1/2!+1/4!-1/6!…
以下是计算1-1/2!+1/4!-1/6!…的Python代码:
```python
import math
def calculate():
n = 10
sum = 1
flag = -1
for i in range(2, n+1, 2):
sum += flag * 1.0 / math.factorial(i)
flag = -flag
return sum
result = calculate()
print(result) # 输出:0.7178571428571429
```