c#如何使用waveOut发声
时间: 2023-07-20 07:38:25 浏览: 187
C++ 使用waveOut实现声音播放
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在 C# 中使用 waveOut 发声可以通过以下步骤实现:
1. 引用 Windows API 函数库 winmm.dll,使用以下语句:
```csharp
[DllImport("winmm.dll")]
static extern int waveOutOpen(out IntPtr hWaveOut, uint uDeviceID, ref WAVEFORMATEX lpFormat, WaveCallback dwCallback, IntPtr dwInstance, uint dwFlags);
```
2. 定义 WAVEFORMATEX 结构体,用于设置音频格式:
```csharp
[StructLayout(LayoutKind.Sequential, Pack = 2)]
struct WAVEFORMATEX
{
public short wFormatTag;
public short nChannels;
public int nSamplesPerSec;
public int nAvgBytesPerSec;
public short nBlockAlign;
public short wBitsPerSample;
public short cbSize;
}
```
3. 创建音频缓冲区,使用以下语句:
```csharp
IntPtr hWaveOut; // waveOut 句柄
WAVEFORMATEX format = new WAVEFORMATEX
{
wFormatTag = 1,
nChannels = 1,
nSamplesPerSec = 8000,
nAvgBytesPerSec = 8000,
nBlockAlign = 1,
wBitsPerSample = 8,
cbSize = 0
};
waveOutOpen(out hWaveOut, 0, ref format, null, IntPtr.Zero, 0);
```
4. 将音频数据写入缓冲区,使用以下语句:
```csharp
[DllImport("winmm.dll")]
static extern int waveOutPrepareHeader(IntPtr hWaveOut, IntPtr lpWaveOutHdr, uint uSize);
[DllImport("winmm.dll")]
static extern int waveOutWrite(IntPtr hWaveOut, IntPtr lpWaveOutHdr, uint uSize);
byte[] buffer = new byte[8000];
IntPtr hBuffer = Marshal.AllocHGlobal(buffer.Length);
Marshal.Copy(buffer, 0, hBuffer, buffer.Length);
IntPtr hHeader = Marshal.AllocHGlobal(Marshal.SizeOf(typeof(WAVEHDR)));
WAVEHDR header = new WAVEHDR
{
lpData = hBuffer,
dwBufferLength = (uint)buffer.Length,
dwBytesRecorded = 0,
dwUser = IntPtr.Zero,
dwFlags = 0,
dwLoops = 0,
lpNext = IntPtr.Zero,
reserved = IntPtr.Zero
};
Marshal.StructureToPtr(header, hHeader, false);
waveOutPrepareHeader(hWaveOut, hHeader, (uint)Marshal.SizeOf(typeof(WAVEHDR)));
waveOutWrite(hWaveOut, hHeader, (uint)Marshal.SizeOf(typeof(WAVEHDR)));
```
以上就是使用 waveOut 在 C# 中发声的基本步骤,具体可以根据实际需求进行调整。
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