求s=1!+2!+...+n!
时间: 2023-12-01 22:43:06 浏览: 32
以下是Python代码,用于计算s=1!+2!+...+n!:
```python
def factorial(n):
if n == 0:
return 1
else:
return n * factorial(n-1)
n = int(input("请输入一个正整数n:"))
sum = 0
for i in range(1, n+1):
m = factorial(i)
sum += m
print("s的值为:", sum)
```
相关问题
用c语言求s=1!+2!+...+n!
以下是用C语言求s=1!+2!+...+n!的代码实现:
```c
#include <stdio.h>
int main(void) {
int n = 0;
int i = 0;
int m = 1;
int sum=0;
printf("请输入n的值:"); scanf("%d", &n);
for (i=1; i<=n; ++i) {
m = m * i;
sum = sum +m;
}
printf ("sum = %d\n", sum);
return 0;
}
```
任意输入n,求S=1!+2!+...+n!
以下是一个任意输入n,求S=1!+2!+...+n!的Python程序:
```python
n = int(input("请输入n的值:"))
sum = 0
factorial = 1
for i in range(1, n+1):
factorial *= i
sum += factorial
print("S的值为:", sum)
```