求s=1!+2!+...+n!

以下是Python代码，用于计算s=1!+2!+...+n!：

def factorial(n):
    if n == 0:
        return 1
    else:
        return n * factorial(n-1)

n = int(input("请输入一个正整数n："))
sum = 0
for i in range(1, n+1):
    m = factorial(i)
    sum += m
print("s的值为：", sum)