解决以下代码的错误： import requests from pyquery import PyQuery as pq def get_num(): headers = { 'User-Agent': 'Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Ubuntu Chromium/44.0.2403.89 Chrome/44.0.2403.89 Safari/537.36', 'Cookie' : 'Q_UDID=ce0129a0-bba3-6764-02e0-ca7893ab2c4f; sessionID=5a7917c3f25cf85fcb1ebf9ea5e53f0b' } data={ "page": "1", "page_num": "10", "search_type": "5" } url = 'https://xcsrc.360zqaq.net/api/backend/bugmanage/buglist ' res = requests.post(url,headers=headers,data=data,timeout=10) content = res.content.decode('utf-8') doc = pq(content) item = doc('.cell el-tooltip') for i in item: b = pq(i).text() print(b) if __name__ == '__main__': get_num()

你的代码有一个错误。在使用 PyQuery 进行选择器操作时，需要使用 `pq()` 函数来创建一个 PyQuery 对象，然后再使用选择器进行操作。所以，你需要将 `item = doc('.cell el-tooltip')` 修改为 `item = doc('.cell.el-tooltip')`。此外，你还需要修改 `item` 的遍历方式，将 `for i in item:` 修改为 `for i in item.items():`。以下是修改后的代码：

import requests
from pyquery import PyQuery as pq


def get_num():
    headers = {
        'User-Agent': 'Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Ubuntu Chromium/44.0.2403.89 Chrome/44.0.2403.89 Safari/537.36',
        'Cookie' : 'Q_UDID=ce0129a0-bba3-6764-02e0-ca7893ab2c4f; sessionID=5a7917c3f25cf85fcb1ebf9ea5e53f0b'
    }

    data={
        "page": "1", "page_num": "10", "search_type": "5"
    }

    url = 'https://xcsrc.360zqaq.net/api/backend/bugmanage/buglist'
    res = requests.post(url, headers=headers, data=data, timeout=10)
    content = res.content.decode('utf-8')
    doc = pq(content)
    items = doc('.cell.el-tooltip')
    for i in items.items():
        b = pq(i).text()
        print(b)


if __name__ == '__main__':
    get_num()

这样修改后，你应该能够正确地获取到文本信息并打印出来了。