case in point中文版
时间: 2023-10-10 12:03:14 浏览: 41
"Case in point"是一个英语短语,意为"典型例子"或者"明确事例"。它通常用于强调或者证明某个观点或者论点。这个短语可以用来引出一个特定的案例或者事件,以证明某种情况确实发生或者存在。
举个例子,假设我们在讨论环境污染对人类健康的影响。我们可以说,"大城市中的空气污染是一个很严重的问题,'case in point'就是北京市。北京市污染水平极高,每年都面临着雾霾的困扰。这个事例可以说明环境污染对人类健康的直接影响。"
在另一个例子中,我们在谈论教育的重要性。我们可能会说,"教育对个人发展至关重要,'case in point'就是某某名人。他出身贫寒,但通过努力学习取得了巨大的成功。这个例子表明了教育的力量和影响。"
总之,"case in point"在英语中用来指出特定的案例或者事件,以证明某一观点或者论点。它帮助我们以一个典型的例子来支持我们的说法或者论证,使得我们的观点更加具有说服力。
相关问题
public void onAccessibilityEvent(AccessibilityEvent event) { int eventType = event.getEventType(); switch (eventType) { case AccessibilityEvent.TYPE_VIEW_CLICKED: Point point = new Point(event.getX(), event.getY()); break; },这段代码出现错误:Cannot resolve method 'getX' in 'AccessibilityEvent'是什么原因
AccessibilityEvent类中并没有getX()方法,getX()是View类中的方法。如果你想获取事件发生的坐标,可以使用AccessibilityEvent的getParcelableData()方法获取一个Parcelable类型的数据,然后将其转换为AccessibilityClickableSpanInfo对象,通过该对象的getX()和getY()方法获取坐标。具体代码如下:
```
public void onAccessibilityEvent(AccessibilityEvent event) {
int eventType = event.getEventType();
switch (eventType) {
case AccessibilityEvent.TYPE_VIEW_CLICKED:
Parcelable data = event.getParcelableData();
if (data instanceof AccessibilityClickableSpanInfo) {
AccessibilityClickableSpanInfo clickableSpanInfo = (AccessibilityClickableSpanInfo) data;
Point point = new Point(clickableSpanInfo.getX(), clickableSpanInfo.getY());
// do something with the point
}
break;
}
}
```
convert 1.75 to floating point representation IEEE 1958
Sure, I can help you with that.
To convert 1.75 to floating point representation IEEE 1958, we need to follow certain steps:
Step 1: Convert the decimal number 1.75 to binary.
1. Convert the integer part 1 to binary -> 1
2. Convert the fraction part 0.75 to binary:
0.75 x 2 = 1.5 (1 goes to the bit after the comma)
0.5 x 2 = 1 (1 goes to the next bit)
0
So 1.75 in binary is represented as 1.11
Step 2: Normalize the binary number
The binary number is normalized by moving the decimal point to the left so that there is only one non-zero digit before the decimal point. In this case, the binary number is already normalized.
Step 3: Determine the sign, exponent, and mantissa
Sign: Since the number is positive, the sign bit is 0.
Exponent: The exponent can be calculated using the formula:
exponent = (number of bits for exponent - 1) + bias
For IEEE 1958 floating point representation, the bias value is 127, and the number of bits for the exponent is 8.
In this case, the exponent is 0 + 127 = 127
Mantissa: The mantissa is the fractional part of the normalized binary number.
In this case, the mantissa is 1.11, which can be represented as:
1.11 = 1 + 1/2 + 1/4 = 1.5
The mantissa is then represented in binary as:
1.5 = 1.1000...
So the sign bit is 0, the exponent in binary is 01111111, and the mantissa in binary is 10000000000000000000000.
Putting it all together, 1.75 in floating point representation IEEE 1958 is:
0 11111111 10000000000000000000000
I hope this helps! Is there anything else I can assist you with?
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