用python写从键盘输入x的值，求, 直到最后一项绝对值小于le−7（即10−7）为止（注：x为弧度值

import math

x = float(input("请输入x的值（弧度制）："))
result = 0
n = 0
while True:
term = ((-1) ** n) * (x ** (2 * n + 1)) / math.factorial(2 * n + 1)
result += term
n += 1
if abs(term) < 10 ** (-7):
break
print("sin(x)的值为：", result)