编写一个python跑酷小游戏
时间: 2023-07-18 16:45:29 浏览: 71
好的,我可以为您提供一个简单的Python跑酷小游戏的示例代码,但是需要注意的是,由于没有图形界面,游戏体验可能不够好。代码如下:
```python
import random
# 初始化游戏地图
MAP_WIDTH = 60
MAP_HEIGHT = 10
MAP_BLANK = " "
MAP_PLAYER = "A"
MAP_OBSTACLE = "X"
MAP_GOAL = "G"
game_map = [[MAP_BLANK for i in range(MAP_WIDTH)] for j in range(MAP_HEIGHT)]
game_map[MAP_HEIGHT-1][0] = MAP_PLAYER
# 随机生成障碍物和终点
obstacle_pos = random.randint(10, 30)
game_map[MAP_HEIGHT-1][obstacle_pos] = MAP_OBSTACLE
goal_pos = random.randint(MAP_WIDTH//2, MAP_WIDTH-1)
game_map[MAP_HEIGHT-1][goal_pos] = MAP_GOAL
# 游戏循环
player_pos = 0
while True:
# 输出游戏地图
for i in range(MAP_HEIGHT):
print("".join(game_map[i]))
# 获取玩家操作
action = input("Move to left or right? (L/R)").upper()
# 更新玩家位置
if action == "L":
if player_pos > 0:
game_map[MAP_HEIGHT-1][player_pos] = MAP_BLANK
player_pos -= 1
game_map[MAP_HEIGHT-1][player_pos] = MAP_PLAYER
elif action == "R":
if player_pos < MAP_WIDTH-1:
game_map[MAP_HEIGHT-1][player_pos] = MAP_BLANK
player_pos += 1
game_map[MAP_HEIGHT-1][player_pos] = MAP_PLAYER
# 判断游戏是否结束
if player_pos == obstacle_pos:
print("Game over! You hit the obstacle!")
break
elif player_pos == goal_pos:
print("Congratulations! You reached the goal!")
break
```
这个示例代码实现的功能比较简单,只有左右移动和避开障碍物到达终点的功能,但是可以作为一个基础框架,可以根据需要进行扩展。
阅读全文