利用给定的一组坐标,实现三次Hermite插值曲线绘制。该曲线绘制做成一个函数形式
时间: 2023-06-04 07:03:59 浏览: 67
好的,这个问题属于数学类问题,我可以为你回答。下面是三次Hermite插值曲线绘制函数的示例代码:
```
import matplotlib.pyplot as plt
import numpy as np
# 定义三次Hermite插值函数
def hermite_interp(x, y, dy):
n = len(x)
coeffs = np.zeros((4, n-1))
for i in range(n-1):
coeffs[0, i] = y[i]
coeffs[1, i] = dy[i]
coeffs[2, i] = (3*(y[i+1]-y[i])/((x[i+1]-x[i])**2)) - ((dy[i+1]+2*dy[i])/(x[i+1]-x[i]))
coeffs[3, i] = ((2*(y[i]-y[i+1]))/((x[i+1]-x[i])**3)) + ((dy[i+1]+dy[i])/((x[i+1]-x[i])**2))
def f(t):
for i in range(n-1):
if x[i] <= t <= x[i+1]:
dt = t - x[i]
return coeffs[0, i] + coeffs[1, i]*dt + coeffs[2, i]*(dt**2) + coeffs[3, i]*(dt**3)
return f
# 给定一组坐标
x = np.array([0, 1, 3, 4])
y = np.array([1, 2, 4, 4])
dy = np.array([1, 1, 0, 0])
# 绘制三次Hermite插值曲线
f = hermite_interp(x, y, dy)
t = np.linspace(x[0], x[-1], 100)
plt.plot(t, f(t))
plt.scatter(x, y)
plt.show()
```
函数 `hermite_interp` 输入参数为自变量 x 和对应的因变量 y、一阶导数 dy,返回三次Hermite插值曲线的函数。在给定的坐标上使用 `hermite_interp` 函数插值,可以绘制出三次Hermite插值曲线。