CUSTOMER_X_COORD(CUST)这句中存在syntax error请再好好检查一下

非常抱歉，你是对的。这是一个语法错误，因为在 Lingo 中，不能在数组名称后面使用括号。正确的语法是在数组名称后面使用方括号，如下所示：

CUSTOMER_X_COORD[CUST] = [2, 3, 8, 7, 6, 5, 1, 9, 6, 4, 5, 3, 1, 7, 2, 9, 8, 4, 6, 10];
CUSTOMER_Y_COORD[CUST] = [5, 1, 2, 3, 4, 7, 10, 2, 6, 9, 3, 1, 4, 5, 7, 10, 4, 5, 8, 9];
CENTER_X_COORD[CENTER] = [1, 3, 6, 8, 10];
CENTER_Y_COORD[CENTER] = [1, 3, 5, 7, 9];
CAPACITY[CUST] = [20, 10, 30, 15, 5, 25, 20, 10, 15, 30, 10, 20, 25, 5, 15, 30, 20, 10, 25, 5];
VEHICLE_NUMBER[CENTER] = [2, 3, 1, 2, 1];

感谢你的指正，希望这次回答更加准确无误。

相关问题

model: sets: row1/1..20/:CUST; row2/1..5/:CENTER; endsets data: CUSTOMER_X_COORD(CUST) := <2, 3, 8, 7, 6, 5, 1, 9, 6, 4, 5, 3, 1, 7, 2, 9, 8, 4, 6, 10>; CUSTOMER_Y_COORD(CUST) := <5, 1, 2, 3, 4, 7, 10, 2, 6, 9, 3, 1, 4, 5, 7, 10, 4, 5, 8, 9>; CENTER_X_COORD(CENTER) := <1, 3, 6, 8, 10>; CENTER_Y_COORD(CENTER) := <1, 3, 5, 7, 9>; EndData DataRef: CUSTOMER_X_COORD, CUSTOMER_Y_COORD, CENTER_X_COORD, CENTER_Y_COORD; EndDataRef Table COST_MATRIX(CUST, CENTER) = SQRT((CUSTOMER_X_COORD(CUST)-CENTER_X_COORD(CENTER))^2 + (CUSTOMER_Y_COORD(CUST)-CENTER_Y_COORD(CENTER))^2); Variables: X(CUST, CENTER), Binary; Y(CENTER), Binary; EndVariables Minimize Total_Cost : = sum((i, j, k | k ~= j), X(i,j,k) * COST_MATRIX(i,j)); Subject to Constraint1(i in CUST): sum(X(i,j,k) * CAPACITY(i) | j in CENTER, k in CENTER) <= sum(Y(j) * VEHICLE_NUMBER(j) | j in CENTER); Constraint2(j in CENTER): sum(Y(j)) = 1; Constraint3(i in CUST): sum(X(i,j,k) | j in CENTER, k in CENTER) = 1; Constraint4(i in CUST, j in CENTER): sum(X(i,j,k) | k in CENTER) <= Y(j); End更改一下这段Lingo代码

以下是对代码进行的一些修改：

1. 在Sets部分，将row1改为CUST，将row2改为CENTER，使得集合名称更直观。

2. 在Variables部分，将变量Y的类型改为Integer，使得变量Y只能取0或1两个值。

3. 在Minimize部分，将目标函数中的不等式符号“~=”改为“<>”，表示不等于。

4. 在Constraint1部分，添加了一个新的参数CAPACITY(i)，表示第i个客户所需的货物容量。

5. 在Constraint2部分，将约束条件改为大于等于1，保证每个中心至少分配给一个客户。

修改后的代码如下：

model:
    Sets:
        CUST /1..20/;
        CENTER /1..5/;
    Endsets

    Data:
        CUSTOMER_X_COORD(CUST) := <2, 3, 8, 7, 6, 5, 1, 9, 6, 4, 5, 3, 1, 7, 2, 9, 8, 4, 6, 10>;
        CUSTOMER_Y_COORD(CUST) := <5, 1, 2, 3, 4, 7, 10, 2, 6, 9, 3, 1, 4, 5, 7, 10, 4, 5, 8, 9>;
        CENTER_X_COORD(CENTER) := <1, 3, 6, 8, 10>;
        CENTER_Y_COORD(CENTER) := <1, 3, 5, 7, 9>;
        CAPACITY(CUST) := <20, 10, 30, 15, 5, 25, 20, 10, 15, 30, 10, 20, 25, 5, 15, 30, 20, 10, 25, 5>;
        VEHICLE_NUMBER(CENTER) := <2, 3, 1, 2, 1>;
    EndData

    DataRef:
        CUSTOMER_X_COORD, CUSTOMER_Y_COORD, CENTER_X_COORD, CENTER_Y_COORD, CAPACITY, VEHICLE_NUMBER;
    EndDataRef

    Table COST_MATRIX(CUST, CENTER) =
        SQRT((CUSTOMER_X_COORD(CUST)-CENTER_X_COORD(CENTER))^2
        + (CUSTOMER_Y_COORD(CUST)-CENTER_Y_COORD(CENTER))^2);

Variables:
    X(CUST, CENTER), Binary;
    Y(CENTER), Integer;
EndVariables

Minimize
    Total_Cost : = sum((i, j, k | k <> j), X(i,j,k) * COST_MATRIX(i,j));
Subject to
    Constraint1(i in CUST):
        sum(X(i,j,k) * CAPACITY(i) | j in CENTER, k in CENTER) <= sum(Y(j) * VEHICLE_NUMBER(j) | j in CENTER);

    Constraint2(j in CENTER):
        sum(Y(j)) >= 1;

    Constraint3(i in CUST):
        sum(X(i,j,k) | j in CENTER, k in CENTER) = 1;

    Constraint4(i in CUST, j in CENTER):
        sum(X(i,j,k) | k in CENTER) <= Y(j);
End

MODEL: SETS: CUST /1..20/; CENTER /1..5/; ENDSETS DATA: CUSTOMER_X_COORD(CUST) = 2 3 8 7 6 5 1 9 6 4 5 3 1 7 2 9 8 4 6 10; CUSTOMER_Y_COORD(CUST) = 5 1 2 3 4 7 10 2 6 9 3 1 4 5 7 10 4 5 8 9; CENTER_X_COORD(CENTER) = 1 3 6 8 10; CENTER_Y_COORD(CENTER) = 1 3 5 7 9; CAPACITY(CUST) = 20 10 30 15 5 25 20 10 15 30 10 20 25 5 15 30 20 10 25 5; VEHICLE_NUMBER(CENTER) = 2 3 1 2 1; ENDDATA DataRef: CUSTOMER_X_COORD, CUSTOMER_Y_COORD, CENTER_X_COORD, CENTER_Y_COORD, CAPACITY, VEHICLE_NUMBER; EndDataRef @Table COST_MATRIX(CUST, CENTER) = @SQRT((CUSTOMER_X_COORD(CUST)-CENTER_X_COORD(CENTER))^2 + (CUSTOMER_Y_COORD(CUST)-CENTER_Y_COORD(CENTER))^2); VARIABLES: X(CUST, CENTER), Binary; Y(CENTER),Integer; ENDVARIABLES Minimize： Total_Cost : = @sum((i, j, k | k <> j), X(i,j,k) * COST_MATRIX(i,j)); Subject to: Constraint1(i in CUST): @sum(X(i,j,k) * CAPACITY(i) | j in CENTER, k in CENTER) <= sum(Y(j) * VEHICLE_NUMBER(j) | j in CENTER); Constraint2(j in CENTER): @sum(Y(j)) >= 1; Constraint3(i in CUST): @sum(X(i,j,k) | j in CENTER, k in CENTER) = 1; Constraint4(i in CUST, j in CENTER): @sum(X(i,j,k) | k in CENTER) <= Y(j); End这段代码放在lingo里无法输出结果，帮我检查并改正一下

这段代码并不是 Lingo 语言，而是 AMPL 语言。你需要使用 AMPL 软件来运行这段代码，而不是 Lingo。

如果你已经在 AMPL 中运行了这段代码，但是无法输出结果，可能是因为缺少输出语句。你可以在 Minimize 语句后面添加一个 print 语句，例如：

Minimize Total_Cost : = @sum((i, j, k | k <> j), X(i,j,k) * COST_MATRIX(i,j));
print Total_Cost;

这样就可以输出最小化总成本的结果了。同样地，你也可以在 Subject to 语句后面添加 print 语句，输出约束条件的结果。