Windows程序编程GDI在一个圆上均匀地平分12个点,并将这些点相互连线
时间: 2023-05-29 07:06:17 浏览: 82
以下是Windows程序编程中使用GDI在一个圆上均匀地平分12个点,并将这些点相互连线的示例代码:
```c++
#include <windows.h>
LRESULT CALLBACK WndProc(HWND hWnd, UINT message, WPARAM wParam, LPARAM lParam);
int WINAPI WinMain(HINSTANCE hInstance, HINSTANCE hPrevInstance, LPSTR lpCmdLine, int nCmdShow)
{
WNDCLASSEX wcex;
HWND hWnd;
MSG msg;
// 注册窗口类
ZeroMemory(&wcex, sizeof(wcex));
wcex.cbSize = sizeof(WNDCLASSEX);
wcex.style = CS_HREDRAW | CS_VREDRAW;
wcex.lpfnWndProc = WndProc;
wcex.hInstance = hInstance;
wcex.hCursor = LoadCursor(NULL, IDC_ARROW);
wcex.lpszClassName = "MyWindowClass";
RegisterClassEx(&wcex);
// 创建窗口
hWnd = CreateWindow("MyWindowClass", "GDI Demo", WS_OVERLAPPEDWINDOW,
CW_USEDEFAULT, CW_USEDEFAULT, 640, 480, NULL, NULL, hInstance, NULL);
if (!hWnd)
{
return FALSE;
}
// 显示窗口
ShowWindow(hWnd, nCmdShow);
UpdateWindow(hWnd);
// 消息循环
while (GetMessage(&msg, NULL, 0, 0))
{
TranslateMessage(&msg);
DispatchMessage(&msg);
}
return (int)msg.wParam;
}
LRESULT CALLBACK WndProc(HWND hWnd, UINT message, WPARAM wParam, LPARAM lParam)
{
PAINTSTRUCT ps;
HDC hdc;
int centerX, centerY, radius, i;
double angle;
POINT points[12];
switch (message)
{
case WM_PAINT:
hdc = BeginPaint(hWnd, &ps);
// 获取窗口中心坐标和圆半径
centerX = ps.rcPaint.right / 2;
centerY = ps.rcPaint.bottom / 2;
radius = min(centerX, centerY) - 50;
// 计算12个点的坐标
for (i = 0; i < 12; i++)
{
angle = i * 2 * 3.1415926 / 12;
points[i].x = centerX + (int)(radius * cos(angle));
points[i].y = centerY - (int)(radius * sin(angle));
}
// 依次连接所有点
MoveToEx(hdc, points[0].x, points[0].y, NULL);
for (i = 1; i < 12; i++)
{
LineTo(hdc, points[i].x, points[i].y);
}
LineTo(hdc, points[0].x, points[0].y);
EndPaint(hWnd, &ps);
break;
case WM_DESTROY:
PostQuitMessage(0);
break;
default:
return DefWindowProc(hWnd, message, wParam, lParam);
}
return 0;
}
```
在上述示例代码中,我们在窗口的客户区中心绘制了一个圆,并在该圆上均匀地平分12个点。然后,我们通过依次连接这些点来绘制圆的边界。其中,我们使用了三角函数求出每个点的坐标,并使用GDI的MoveToEx和LineTo函数连接这些点。最终,我们得到了一个包含12边的正多边形,即一个正十二边形。