编辑一个基础版扫雷游戏
时间: 2023-05-20 19:01:50 浏览: 51
好的,我可以为您提供一个基础版的扫雷游戏的代码。以下是一个简单的实现:
```python
import random
class Minesweeper:
def __init__(self, width, height, num_mines):
self.width = width
self.height = height
self.num_mines = num_mines
self.board = [[0 for _ in range(width)] for _ in range(height)]
self.mines = set()
self.game_over = False
# randomly place mines
while len(self.mines) < num_mines:
x, y = random.randint(0, width-1), random.randint(0, height-1)
if (x, y) not in self.mines:
self.mines.add((x, y))
self.board[y][x] = -1
# calculate numbers for non-mine cells
for y in range(height):
for x in range(width):
if self.board[y][x] == -1:
continue
for dx in range(-1, 2):
for dy in range(-1, 2):
if (dx, dy) == (0, 0):
continue
if 0 <= x+dx < width and 0 <= y+dy < height and self.board[y+dy][x+dx] == -1:
self.board[y][x] += 1
def __str__(self):
return '\n'.join([' '.join([self.cell_string(x, y) for x in range(self.width)]) for y in range(self.height)])
def cell_string(self, x, y):
if self.game_over and (x, y) in self.mines:
return '*'
elif self.board[y][x] == -1:
return 'X'
elif self.board[y][x] == 0:
return '.'
else:
return str(self.board[y][x])
def reveal(self, x, y):
if self.game_over or (x, y) in self.mines:
self.game_over = True
return False
elif self.board[y][x] > 0:
return True
else:
for dx in range(-1, 2):
for dy in range(-1, 2):
if (dx, dy) == (0, 0):
continue
if 0 <= x+dx < self.width and 0 <= y+dy < self.height and self.board[y+dy][x+dx] != -1:
self.reveal(x+dx, y+dy)
return True
```
这个代码实现了一个 Minesweeper 类,可以通过以下方式使用:
```python
game = Minesweeper(10, 10, 10) # create a 10x10 board with 10 mines
print(game) # print the initial board state
game.reveal(0, 0) # reveal the cell at (0, 0)
print(game) # print the updated board state
```
这个实现还比较简单,没有实现标记雷的功能,也没有实现游戏胜利的判断。如果您需要更完整的实现,可以在此基础上进行扩展。
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