可以用C语言实现它码？

是的，可以用C语言实现流水线调度问题的算法。以下是C语言的代码实现：

1. 输入流水线的预约表：

#include <stdio.h>
#include <stdlib.h>

#define MAX_FUNC_SEGMENTS 10

// 定义流水线预约表结构体
struct PipelineReservationTable {
    int func_segment_time[MAX_FUNC_SEGMENTS];
    int task_schedule_order[MAX_FUNC_SEGMENTS];
    int num_func_segments;
};

// 读取流水线预约表
void read_pipeline_reservation_table(struct PipelineReservationTable *prt) {
    int i;

    printf("请输入流水线的时间周期：");
    scanf("%d", &prt->func_segment_time[0]);

    printf("请输入流水线的功能段数：");
    scanf("%d", &prt->num_func_segments);

    printf("请输入每个功能段的处理时间：");
    for (i = 1; i <= prt->num_func_segments; i++) {
        scanf("%d", &prt->func_segment_time[i]);
    }

    printf("请输入任务调度顺序：");
    for (i = 1; i <= prt->num_func_segments; i++) {
        scanf("%d", &prt->task_schedule_order[i]);
    }
}

2. 求出延迟禁止表和冲突向量：

#define MAX_TASKS 10

// 定义延迟禁止表结构体
struct DelayForbiddenTable {
    int delay[MAX_TASKS];
    int forbidden[MAX_FUNC_SEGMENTS][MAX_TASKS];
};

// 计算延迟禁止表和冲突向量
void calc_delay_forbidden_table(struct PipelineReservationTable *prt, struct DelayForbiddenTable *dft) {
    int i, j;

    // 计算延迟禁止表
    dft->delay[0] = 0;
    for (i = 1; i <= prt->num_func_segments; i++) {
        dft->delay[i] = dft->delay[i-1] + prt->func_segment_time[prt->task_schedule_order[i]];
    }

    // 计算冲突向量
    for (i = 1; i <= prt->num_func_segments; i++) {
        for (j = 1; j <= MAX_TASKS; j++) {
            dft->forbidden[i][j] = 0;
        }
    }
    for (i = 1; i <= prt->num_func_segments; i++) {
        for (j = 1; j <= MAX_TASKS; j++) {
            if (j > i) {
                dft->forbidden[i][j] = dft->forbidden[i][j-1] + prt->func_segment_time[prt->task_schedule_order[j-1]];
            } else {
                dft->forbidden[i][j] = dft->forbidden[i][j-1];
            }
        }
    }
}

3. 构造流水线状态转移图：

#define MAX_STATES 100

// 定义流水线状态结构体
struct PipelineState {
    int task_id;
    int state_time;
};

// 构造流水线状态转移图
void build_pipeline_state_transition_graph(struct PipelineReservationTable *prt, struct DelayForbiddenTable *dft, struct PipelineState state_graph[MAX_STATES][MAX_TASKS+1]) {
    int i, j, k;
    int num_states = 0;

    // 初始化状态转移图
    for (i = 0; i < MAX_STATES; i++) {
        for (j = 0; j <= MAX_TASKS; j++) {
            state_graph[i][j].task_id = -1;
            state_graph[i][j].state_time = -1;
        }
    }

    // 根据流水线预约表和延迟禁止表构造状态转移图
    for (i = 1; i <= prt->num_func_segments; i++) {
        for (j = 1; j <= MAX_TASKS; j++) {
            if (dft->forbidden[i][j] <= dft->delay[j-1]) {
                state_graph[num_states][j].task_id = j;
                state_graph[num_states][j].state_time = dft->delay[j-1] + prt->func_segment_time[prt->task_schedule_order[i]];
                for (k = 1; k < j; k++) {
                    if (state_graph[num_states][k].state_time > state_graph[num_states][j].state_time) {
                        state_graph[num_states][k].state_time = state_graph[num_states][j].state_time;
                    }
                }
                num_states++;
            }
        }
    }
}

4. 寻找最小等间隔调度：

// 计算最小等间隔调度
void calc_minimum_uniform_schedule(struct PipelineReservationTable *prt, struct PipelineState state_graph[MAX_STATES][MAX_TASKS+1], int *min_time, int *min_schedule[MAX_TASKS+1]) {
    int i, j, k;
    int num_states = 0;
    int state_time[MAX_STATES] = {0};
    int curr_time = 0;

    // 初始化最小等间隔调度
    for (i = 1; i <= MAX_TASKS; i++) {
        min_schedule[i] = 0;
    }
    *min_time = 0;

    // 计算每个状态的处理时间
    for (i = 0; i < MAX_STATES; i++) {
        if (state_graph[i][1].task_id == -1) {
            break;
        }
        for (j = 1; j <= MAX_TASKS; j++) {
            if (state_graph[i][j].task_id == -1) {
                break;
            }
            if (state_graph[i][j].state_time > state_time[i]) {
                state_time[i] = state_graph[i][j].state_time;
            }
        }
    }

    // 计算最小等间隔调度
    curr_time = state_time[0];
    for (i = 1; i < num_states; i++) {
        if (state_time[i] > curr_time) {
            curr_time = state_time[i];
        }
    }
    *min_time = curr_time;
    for (i = 1; i <= prt->num_func_segments; i++) {
        min_schedule[prt->task_schedule_order[i]] = curr_time;
        curr_time -= prt->func_segment_time[prt->task_schedule_order[i]];
    }
}

5. 寻找最佳调度，并给出最小平均延迟和流水线的最大吞吐率：

// 计算最佳调度和流水线的最大吞吐率
void calc_best_schedule_and_max_throughput_rate(struct PipelineReservationTable *prt, struct PipelineState state_graph[MAX_STATES][MAX_TASKS+1], int *best_time, int *best_schedule[MAX_TASKS+1], double *max_throughput_rate) {
    int i, j, k;
    int num_states = 0;
    int state_time[MAX_STATES] = {0};
    int curr_time = 0;
    double throughput_rate[MAX_STATES] = {0};

    // 初始化最佳调度和最大吞吐率
    for (i = 1; i <= MAX_TASKS; i++) {
        best_schedule[i] = 0;
    }
    *best_time = 0;
    *max_throughput_rate = 0.0;

    // 计算每个状态的处理时间和吞吐率
    for (i = 0; i < MAX_STATES; i++) {
        if (state_graph[i][1].task_id == -1) {
            break;
        }
        for (j = 1; j <= MAX_TASKS; j++) {
            if (state_graph[i][j].task_id == -1) {
                break;
            }
            if (state_graph[i][j].state_time > state_time[i]) {
                state_time[i] = state_graph[i][j].state_time;
            }
        }
        throughput_rate[i] = (double)j / state_time[i];
    }

    // 计算最佳调度和最大吞吐率
    *max_throughput_rate = 0.0;
    for (i = 0; i < num_states; i++) {
        if (throughput_rate[i] > *max_throughput_rate) {
            *max_throughput_rate = throughput_rate[i];
            *best_time = state_time[i];
            for (j = 1; j <= prt->num_func_segments; j++) {
                best_schedule[prt->task_schedule_order[j]] = state_graph[i][j].state_time - prt->func_segment_time[prt->task_schedule_order[j]];
            }
        }
    }
}

6. 按此流水线调度方案，输入n个任务，画出时空图，求实际吞吐率：

#define MAX_TASKS 10

// 画出时空图
void draw_time_space_diagram(struct PipelineReservationTable *prt, int *schedule, int num_tasks, int task_time[MAX_TASKS+1]) {
    int i, j, k;
    int curr_time = 0;
    int state[MAX_TASKS+1] = {0};

    // 初始化状态
    for (i = 1; i <= num_tasks; i++) {
        state[i] = 0;
    }

    // 计算任务的处理时间
    for (i = 1; i <= num_tasks; i++) {
        task_time[i] = 0;
        for (j = 1; j <= prt->num_func_segments; j++) {
            if (prt->task_schedule_order[j] == i) {
                task_time[i] += prt->func_segment_time[j];
            }
        }
    }

    // 画出时空图
    printf("\n时空图：\n");
    for (i = 1; i <= num_tasks; i++) {
        curr_time = schedule[i] + task_time[i];
        printf("任务%d：", i);
        for (j = 0; j < schedule[i]; j++) {
            printf("-");
        }
        for (j = schedule[i]; j < curr_time; j++) {
            printf("*");
        }
        for (j = curr_time; j < prt->func_segment_time[0]; j++) {
            printf("-");
        }
        printf("\n");
        for (j = 1; j <= prt->num_func_segments; j++) {
            if (prt->task_schedule_order[j] == i) {
                printf("功能段%d：", j);
                for (k = 0; k < prt->func_segment_time[j]; k++) {
                    printf("-");
                }
                printf("\n");
            }
        }
        printf("\n");
    }
}

// 计算实际吞吐率
double calc_actual_throughput_rate(struct PipelineReservationTable *prt, int num_tasks, int task_time[MAX_TASKS+1]) {
    int i;
    double total_time = 0.0;

    for (i = 1; i <= num_tasks; i++) {
        total_time += task_time[i];
    }
    return (double)num_tasks / total_time;
}

以上是用C语言实现流水线调度问题的完整代码。需要注意的是，此代码仅供参考，实际应用中需要