可以将下面的代码转换成system Verilog吗:module top_module( input in, output out ); assign out = in; endmodule
时间: 2023-03-30 16:03:45 浏览: 127
可以将下面的代码转换成System Verilog语言:
module top_module(
input in,
output out
);
assign out = in;
endmodule
相关问题
//XW_crc_p.v `pragma protect begin module DW_crc_p( data_in, crc_in, crc_ok, crc_out ); parameter integer data_width = 16; parameter integer poly_size = 16; parameter integer crc_cfg = 7; parameter integer bit_order = 3; parameter integer poly_coef0 = 4129; parameter integer poly_coef1 = 0; parameter integer poly_coef2 = 0; parameter integer poly_coef3 = 0; input [data_width-1:0] data_in; input [poly_size-1:0] crc_in; output crc_ok; output [poly_size-1:0] crc_out; `define DW_max_data_crc_1 (data_width>poly_size?data_width:poly_size) wire [poly_size-1:0] crc_in_inv; wire [poly_size-1:0] crc_reg; wire [poly_size-1:0] crc_out_inv; wire [poly_size-1:0] crc_chk_crc_in; reg [poly_size-1:0] crc_inv_alt; reg [poly_size-1:0] crc_polynomial; `include "bit_order_crc_function.inc" `include "bit_order_data_function.inc" `include "calculate_crc_w_in_function.inc" `include "calculate_crc_function.inc" `include "calculate_crc_crc_function.inc" generate //begin genvar bit_idx; reg [63:0] crc_polynomial64; reg [15:0] coef0; reg [15:0] coef1; reg [15:0] coef2; reg [15:0] coef3; assign coef0= poly_coef0; assign coef0= poly_coef1; assign coef0= poly_coef2; assign coef0= poly_coef3; assign crc_polynomial64 = {coef3, coef2, coef1, coef0}; assign crc_pollynomial = crc_polynomial64[poly_size-1:0]; case(crc_cfg/2) 0: assign crc_inv_alt = {poly_size{1'b0}}; 1: for(bit_idx = 0; bit_idx<poly_sizel bit_idx=bit_idx+1) assign crc_inv_alt[bit_idx] = (bit_idx % 2)? 1'b0:1'b1; 2: for(bit_idx=0; bit_idx<poly_size; bit_idx=bit_idx+1) assign crc_inv_alt[bit_idx] = (bit_idx % 2)?1'b1:1'b0; 3: assign crc_inv_alt = { poly_size{1'b1}}; endcase endgenerate assign crc_in_inv = bit_order_crc(crc_in) ^ crc_inv_alt; assign crc_reg = calculate_crc(bit_order_data(data_in)); assign crc_out_inv = crc_reg; assign crc_out = bit_order_crc(crc_out_inv)^ crc_inv_alt; assign crc_chk_crc_in = calculate_crc_crc(crc_reg, crc_in_inv); assign crc_ok = (crc_chk_crc_in ==0); `undef DW_max_data_crc_1 endmodule `pragma protect end can you write a testbench for this piece of CRC verilog code so that this verilog file and the testbench can be used togerther by vcs to verify the correctness of this verilog file?
Sure, here's a basic testbench for the `DW_crc_p` module:
```
`timescale 1ns/1ps
module testbench;
// Inputs
reg [15:0] data_in;
reg [15:0] crc_in;
// Outputs
wire crc_ok;
wire [15:0] crc_out;
// Instantiate the DUT
DW_crc_p dut (
.data_in(data_in),
.crc_in(crc_in),
.crc_ok(crc_ok),
.crc_out(crc_out)
);
initial begin
// Initialize inputs
data_in = 16'h1234;
crc_in = 16'h5678;
// Wait for a few cycles
#10;
// Change inputs
data_in = 16'h5678;
crc_in = 16'h1234;
// Wait for a few cycles
#10;
// Add more test cases as needed
// Check outputs
$display("crc_ok = %b, crc_out = %h", crc_ok, crc_out);
end
endmodule
```
This testbench simply initializes the `data_in` and `crc_in` inputs, waits for a few cycles, changes the inputs, waits for a few more cycles, and then checks the `crc_ok` and `crc_out` outputs using the `$display` system task. You can add more test cases as needed by changing the input values and checking the output values. To run the testbench with the `DW_crc_p` module, you can use the following command:
```
vcs -debug testbench.v DW_crc_p.v
```
This will compile both the testbench and the `DW_crc_p` module, and then run the simulation. You can view the simulation results using the `dve` GUI or by examining the output in the terminal window.
sure. the piece of system verilog code is as below: module inner_submod ( input logic [9:-1][2:0] sub_input, output logic [9:-1][2:0] sub_output ); assign sub_output = sub_input + 1; endmodule module test_top; typedef struct packed { logic [9:-1][2:0] a; } ST1; typedef struct { ST1 st1; ST1 st2[2:0]; } ST2; ST2 st2 = '{st1: {a: '{3'b1, 3'b0, 12'b1}}, st2: '{ '{a: '{3'b1, 3'b0, 12'b1}}, '{a: '{3'b1, 3'b0, 12'b1}}, '{a: '{3'b1, 3'b0, 12'b1}} }}; inner_submod submod1 ( .sub_input(st2.st2[0].a), .sub_output(st2.st2[0].a) ); inner_submod submod2 ( .sub_input(st2.st2[0].a), .sub_output(st2.st2[0].a) ); inner_submod submod3 ( .sub_input(st2.st2[1].a), .sub_output(st2.st2[1].a) ); initial begin $display("st2:%s",st2); end and the error reported by vcs is: Error-[SE] Syntax error Following verilog source has syntax error : "sc_assignment_pattern_041.sv", 12: token is '{' module inner_submod {
The syntax error is caused by the way you are initializing the ST2 struct. Instead of using the '{...}' syntax, you should use the '{...} with {...} with {...}' syntax to initialize nested structs. Here is the modified code:
```
module inner_submod (
input logic [9:-1][2:0] sub_input,
output logic [9:-1][2:0] sub_output
);
assign sub_output = sub_input + 1;
endmodule
module test_top;
typedef struct packed {
logic [9:-1][2:0] a;
} ST1;
typedef struct {
ST1 st1;
ST1 st2[2:0];
} ST2;
ST2 st2 = '{st1: {a: '{3'b1, 3'b0, 12'b1}}, st2: '{ '{a: '{3'b1, 3'b0, 12'b1}} with
'{a: '{3'b1, 3'b0, 12'b1}} with
'{a: '{3'b1, 3'b0, 12'b1}} }}';
inner_submod submod1 (
.sub_input(st2.st2[0].a),
.sub_output(st2.st2[0].a)
);
inner_submod submod2 (
.sub_input(st2.st2[0].a),
.sub_output(st2.st2[0].a)
);
inner_submod submod3 (
.sub_input(st2.st2[1].a),
.sub_output(st2.st2[1].a)
);
initial begin
$display("st2:%s",st2);
end
endmodule
```
This should resolve the syntax error reported by vcs.
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