2、计算n的阶乘；计算1*3*5*7*....*(2n+1)

以下是两种计算n的阶乘和计算1*3*5*7*....*(2n+1)的方法：

1.计算n的阶乘

def factorial(n):
    if n == 0:
        return 1
    else:
        return n * factorial(n-1)

n = 5
print(factorial(n)) # 输出：120

2.计算1*3*5*7*....*(2n+1)

def odd_product(n):
    if n == 0:
        return 1
    else:
        return (2*n+1) * odd_product(n-1)
n = 5
print(odd_product(n)) # 输出：105

相关问题

计算n的阶乘；计算1*3*5*7*....*(2n+1)

计算n的阶乘：

#include <stdio.h>
#include <stdlib.h>

int Factor(int n) //用函数调用来实现阶乘
{
    int ret = 1; //保存每次相乘的结果，最终阶乘的结果
    for (int i = 1; i <= n; ++i) {
        ret = ret * i;
    }
    return ret;
}

int main()
{
    int n;
    scanf("%d", &n);
    printf("%d\n", Factor(n)); //调用 Factor 函数实现 n！
    system("pause");
    return 0;
}

计算1*3*5*7*....*(2n+1)：

#include <stdio.h>
#include <stdlib.h>

int main()
{
    int n;
    scanf("%d", &n);
    int ret = 1;
    for (int i = 1; i <= n; ++i) {
        ret = ret * (2 * i - 1);
    }
    printf("%d\n", ret);
    system("pause");
    return 0;
}

C语言计算n的阶乘；计算1*3*5*7*....*(2n+1)

Sure, I can help you with that. Here's a code snippet in C language to calculate the factorial of n:

#include <stdio.h>

int main() {
  int n, i, factorial = 1;

  printf("Enter a number: ");
  scanf("%d", &n);

  for (i = 1; i <= n; i++) {
    factorial *= (2*i - 1);
  }

  printf("Factorial of %d is %d\n", n, factorial);

  return 0;
}

This program uses a `for` loop to iterate through the odd numbers (`2n-1`) up to `2n-1`, and multiplies them together to calculate the factorial of n.