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首页C#初学者进阶：第4部分，构建UWP应用与用户界面设计

C#初学者进阶：第4部分，构建UWP应用与用户界面设计

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"《Begin to Code with C# 第四部分：英文原版》由Rob Miles编著，是微软出版的一本面向初学者的C#编程教程。在这一部分，作者带你进入开发者角色的全新阶段，通过实际操作让你掌握编写可以销售的应用程序。课程不再局限于Snaps框架，它最初隐藏了Windows 10程序开发的一些复杂性，但并非完全抛弃，而是逐步引入更深入的理解。在第4章，你将开始脱离Snaps框架，学习设计用户界面，这是应用程序与用户交互的核心。用户界面就像商店的橱窗，吸引人且易用的设计能够激发用户使用软件的积极性。本章的教学内容包括如何利用对象构建直观、吸引人的界面，让读者理解用户界面设计的重要性，并掌握设计原则和最佳实践。接下来，你将学习现代程序如何处理外部事件，这涉及到编程中的事件驱动模型。理解并能处理这些事件对于编写响应用户行为、适应外部环境变化的软件至关重要。这部分的学习不仅限于理论，还包括实际编码示例，让你在实践中提升技能。通过本章的学习，你将具备创建能够吸引更多用户的软件的能力，同时也能更好地理解和利用C#语言在Windows 10平台上的各种特性。记住，尽管本书中的示例与商业软件之间存在细微差别，但核心编程原理和实践经验是一致的，为你的编程生涯打下坚实的基础。随着技术的深入，你将能够开发出真正具有商业价值的应用，实现从初学者到专业开发者的飞跃。"

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Figure 16-6 Closing a window.

We can run our empty application in the same way as we have been running Snaps

applications. Click the run button (the green arrow) on the top row of controls (being

sure that the text next to it shows Local Machine). When you click the run button,

the program is compiled, loaded into memory, and then allowed to run. Figure 16-7

shows the result.

Figure 16-7 Running an empty program.

The empty program looks pretty much as you would expect, although you might

be curious about the two numbers in the top-left corner of the application window.

These are performance counters that tell you the demands your application is placing

on the host computer and the rate that the display is being updated. They are not

particularly important just at the moment, so you can ignore them for now.

Bearing in mind that all we have done is make an empty program, we do have a lot of

functionality. We can drag the window around the screen, change its size, maximize

and minimize it, and close the application down. We could even submit the solution

to be sold on the Windows Store, although it is unlikely it would be approved for sale

because it currently doesn’t do anything.

488 Chapter 16 Creating a user interface using objects

Stopping a Windows application

Question: How do we stop a Windows application?

Answer: In the programs that we have written up until now, the StartProgram method

from Snaps has been called at the start of the program, and when this method finishes,

the program ends. A Windows 10 application doesn’t work like this, however. The pro-

gram will “run” until the user closes it or the computer is switched off.

Of course, a Windows 10 application is not really running in the same sense as our earlier

programs, in that most of the time it is asleep until the user actually does something. Our

Adding Machine Tutor program will spend most of its time waiting for the user to type in

some numbers or press the button to trigger the calculation behavior.

If you need a program to get control when the user closes the program—perhaps to save

some data—you can connect a method to the event that occurs when the user closes the

program.

Creating the user interface using XAML

The next step is to add some elements to the user interface. We’ll do this by adding

some content to the XAML file that describes the page. The XAML that describes the

main page of the application is held in a file named MainPage.xaml. First, you need

to stop the application if it still running. Then open MainPage.xaml by double-

clicking it in Solution Explorer, as shown in Figure 16-8.

Figure 16-8 Opening the MainPage.xaml file.

CODE ANALYSIS

489

Creating a new application

Opening the file displays it in an editing view that lets you see the XAML that defines

the design along with a preview of how the page will look, as you can see in Figure

16-9.

Figure 16-9 Editing XAML in Visual Studio.

The editing area is split into two regions. At the top you have a preview of the inter-

face as the user will see it. At the bottom you have the XAML that describes the ele-

ments on the page. We are going to start by editing the XAML file.

At the very bottom of the XAML file is the Grid element that contains the elements

that appear on the screen. You can see the top row of the Grid description at the

bottom of Figure 16-9. We can add an element to the screen by adding XAML to the

Grid:

<TextBox Name="firstNumberTextBox" Width="100" Margin="8"

TextAlignment="Center"></TextBox>

</StackPanel>

</Grid>

This is the definition of the first TextBox on the display. If we run the application again,

the TextBox is displayed at the top of the application, as shown in Figure 16-10.

490 Chapter 16 Creating a user interface using objects

Figure 16-10 A single TextBox on the screen.

You can enter text into the TextBox. The text you enter is centered inside the TextBox

because the TextAlignment property for the TextBox has been set to Center. Now go

ahead and add the other elements to the display at this point.

<TextBlock Text="Adding Machine" TextAlignment="Center" Margin="8"

FontSize="16"></TextBlock>

<TextBox Name="firstNumberTextBox" Width="100" Margin="8"

TextAlignment="Center"></TextBox>

<TextBox Name="secondNumberTextBox" Width="100" Margin="8"

TextAlignment="Center"></TextBox>

<Button Content="Equals" Name="equalsButton" HorizontalAlignment="Center"

Margin="8"></Button>

</TextBlock>

</StackPanel>

These XAML statements define the elements that make up the adding machine tutor

display. This XAML looks a bit like a program, but it is actually quite different. It is a

declaration of all the display elements that the program will be using. Visual Studio

will work through this file and create the display elements when the program is com-

piled. If you enter this text into MainPage.xaml, you can see the elements appear in

491

Creating a new application

the preview window above the text. If you run the program, you will see the elements

displayed on the screen as you have specified, which you can see in Figure 16-11.

Figure 16-11 Adding machine tutor.

If you change the size of the program window by dragging a corner of it on the

screen, you’ll notice that the elements always stay in the center. Windows will auto-

matically update the layout if the size of the enclosing window changes. The nice thing

about this kind of design is that it will display correctly on any device, from an 84-inch

Surface Hub screen to a much smaller Windows Phone.

Positioning elements on a XAML display

I’ve been advising you to use storyboards to set out what a program should look like, and

XAML provides a great way to take storyboard designs and build them into the application.

However, when you are planning your designs, you need to have an understanding of how

dimensions are specified within XAML.

Question: How do we measure things within a XAML design?

Answer: Simple question, complicated answer. In the old days, it was easy to express

dimensions on displays. We just measured everything in pixels. (Pixel is an abbreviation of

“picture element” and is a single addressable dot on a display.) A dimension of 100 meant

100 actual dots on the screen. This approach worked well because screens were low reso-

lution and there weren’t many different sizes in use. In addition, a program would only be

expected to work on one platform.

Nowadays, there are many different sizes of display, from tiny tablets to enormous wall-

mounted screens. And just to make things worse, the displays themselves vary greatly in

the number of pixels they contain. Some devices have LCD panels with hundreds of pixels

per inch; others make do with a much lower resolution. Sizing everything in pixels no

longer works.

CODE ANALYSIS

492 Chapter 16 Creating a user interface using objects

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iOS Game Development Developing Games for iPad, iPhone, and iPod Touch.pdf

Unity 2017 is the latest version of this industry leading development platform and C# is a ubiquitous programming language perfect for any programmer to begin with. Using the latest development ...

module DW01_add_tb; // Declare inputs and outputs reg [3:0] A; reg [3:0] B; reg CI; wire [3:0] SUM; wire CO; // Instantiate design under test DW01_add dut( .A(A), .B(B), .CI(CI), .SUM(SUM), .CO(CO) ); // Initialize inputs initial begin A = 4'b0000; B = 4'b0000; CI = 0; end // Adder test case task test_adder; // Test case 1: 0 + 0 with carry-in of 0 A = 4'b0000; B = 4'b0000; CI = 0; #10; if (SUM !== 4'b0000 || CO !== 1'b0) $display("Test failed! 0 + 0 should be 0 with carry-out of 0"); // Test case 2: 7 + 3 with carry-in of 0 A = 4'b0111; B = 4'b0011; CI = 0; #10; if (SUM !== 4'b1010 || CO !== 1'b0) $display("Test failed! 7 + 3 should be 10 with carry-out of 0"); // Test case 3: 5 + 11 with carry-in of 1 A = 4'b0101; B = 4'b1011; CI = 1; #10; if (SUM !== 4'b0001 || CO !== 1'b1) $display("Test failed! 5 + 11 should be 16 with carry-out of 1"); // Test case 4: 15+15 with carry-in of 1 A = 4'b1111; B = 4'b1111; CI = 1; #10; if (SUM !== 4'b1110 || CO !== 1'b1) $display("Overflow!!!"); endtask // Run test cases initial begin test_adder(); $finish; end endmodule // DW01_add_tb If I want to replace the delays, i.e, #10; in this piece of verilog code, by below code: integer cyc; initial cyc=1; always @ (posedge clk) begin cyc <= cyc+1; if(cyc==1)begin in_val1 <=4'd4; end else if (cyc==2) begin if (out_val1 !==8'b1) $stop; in_val <=4'd3; end else if (cyc==3)begin if(out_val1 !== 8'b10)$stop; in_val1 <= 4'd7; end else if(cyc==4) begin $write("ALL Finished \n"); $finish; end end in other words, using pound delay # is not allowed, how should I modify the code?

To replace the delays with the code you provided, you can use a counter to keep track of the number of clock cycles and use an if-else statement to control the input values at each cycle. Here's an ...

module DW01_add_tb; // Declare inputs and outputs reg [3:0] A; reg [3:0] B; reg CI; wire [3:0] SUM; wire CO; // Instantiate design under test DW01_add dut( .A(A), .B(B), .CI(CI), .SUM(SUM), .CO(CO) ); // Initialize inputs initial begin A = 4'b0000; B = 4'b0000; CI = 0; end // Adder test case task test_adder; // Test case 1: 0 + 0 with carry-in of 0 A = 4'b0000; B = 4'b0000; CI = 0; #10; if (SUM !== 4'b0000 || CO !== 1'b0) $display("Test failed! 0 + 0 should be 0 with carry-out of 0"); // Test case 2: 7 + 3 with carry-in of 0 A = 4'b0111; B = 4'b0011; CI = 0; #10; if (SUM !== 4'b1010 || CO !== 1'b0) $display("Test failed! 7 + 3 should be 10 with carry-out of 0"); // Test case 3: 5 + 11 with carry-in of 1 A = 4'b0101; B = 4'b1011; CI = 1; #10; if (SUM !== 4'b0001 || CO !== 1'b1) $display("Test failed! 5 + 11 should be 16 with carry-out of 1"); // Test case 4: 15+15 with carry-in of 1 A = 4'b1111; B = 4'b1111; CI = 1; #10; if (SUM !== 4'b1110 || CO !== 1'b1) $display("Overflow!!!"); endtask // Run test cases initial begin test_adder(); $finish; end endmodule // DW01_add_tb If I want to add clock signal to this testbench, how should I modify the code?

To add a clock signal to this testbench, you can modify the code by declaring a clock signal as an input and using it to drive the testbench. Here's an example modification to the code: ``` module DW...

package step1; import java.lang.Thread; public class MyThread extends Thread { private int num;//任务就是在子线程中计算num的阶乘 public MyThread() { this(0); } //constructor，创建实例的时候初始化参数 public MyThread(int num) { /begin your code here/ num=0; /end your code/ } @Override public void run() { //重写run方法，在子线程中想要执行的代码写在run方法中 int result = 1;//result保存计算出的结果 /begin your code here/ for(int i=1;i<=num;i++) { result*=i; } /end your code/ //直接输出结果 System.out.println(result); } }

/begin your code here/ this.num=num; /end your code/ } ``` 在for循环中，需要将i从1循环到num，而不是从0循环到num-1，因此需要修改如下： ``` /begin your code here/ for(int i=1;i;i++) { result*=i; }...

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module test; typedef struct packed { logic [9:-1][2:0] a; ///REQ-EXT-10001, REQ-EXT-10004 } ST1; typedef struct { ST1 st1; ST1 st2[]; logic [7:0] b; //REQ-EXT-10002; }ST4 initial begin ST4 st4; st4.st1.a[0][0]=1; for (int i=0; i<5; i++) begin st4.st1.push_back(i+1); end st4_1.b = 8'hAA; $display("%", st2); //CHECK-001:'{a:'h1}, st2:'{'a:'h1}, '{a:'h0},'{a:h1}}} end endmodule when compiled by vcs, it reports 3 errors, the errors are: Error-[MFNF] Member not found sc_assignment_pattern_030.sv,29 "st4.st1." Could not find member 'push_back' in structure 'ST1', at "sc_assignment_pattern_030.sv",15. Error-[XMRE] Cross-module reference resolution error sc_assignment_pattern_030.sv,31 Error found while trying to resolve cross-module reference.token 'st4_1'. Originating module 'test'. Source info:st4_1.b = 8'haa; Error-[IND] Identifier 'st2' has not been declared yet. If this error is not expected, please check if you have set 'default_nettype to none. How should I fix these 3 errors so that this piece of system verilog code can be compiled succeessfully by vcs? thanks a lot

To fix this error, you need to change the code to use 'st4' instead of 'st4_1': ``` ST4 st4; st4.st1.a[0][0]=1; for (int i=0; i; i++) begin ST1 tmp; tmp.a[0][0] = i+1; st4.st2.push_back(tmp); end...

static void MX_GPIO_Init(void) { /* USER CODE BEGIN MX_GPIO_Init_1 / / USER CODE END MX_GPIO_Init_1 / / GPIO Ports Clock Enable / __HAL_RCC_GPIOB_CLK_ENABLE(); __HAL_RCC_GPIOC_CLK_ENABLE(); / USER CODE BEGIN MX_GPIO_Init_2 / / USER CODE END MX_GPIO_Init_2 / } / USER CODE BEGIN 4 / / USER CODE END 4 */这是什么

在这个特定的示例中，函数中有两个 `/* USER CODE BEGIN */` 和 `/* USER CODE END */` 的注释块。这是为了让用户在这些注释块之间插入自定义的代码。一般来说，你可以在 `/* USER CODE BEGIN MX_GPIO_Init_1 */` ...

students(student_id, name, year, GPA, programs_code) instructors(instructor_id, name, title, salary, programs_code) programs(code, name, division, instructor_id) course(course_name, credit, domain, course_number) enroll(student_id, instructor_id, course_name) 1. Create tables according to the schema. 2. Use check or assertion to make sure instructors salary > 5000. 3. Use trigger to deal with cascade delete.

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module DW01_add_tb; // Declare inputs and outputs reg clk; reg [3:0] A; reg [3:0] B; reg CI; wire [3:0] SUM; wire CO; // Instantiate design under test DW01_add dut( .A(A), .B(B), .CI(CI), .SUM(SUM), .CO(CO) ); // Initialize inputs initial begin A = 4'b0000; B = 4'b0000; CI = 0; clk=0; end // Adder test case task test_adder; // Test case 1: 0 + 0 with carry-in of 0 A = 4'b0000; B = 4'b0000; CI = 0; //#10; //if (SUM !== 4'b0000 || CO !== 1'b0) $display("Test failed! 0 + 0 should be 0 with carry-out of 0"); // Test case 2: 7 + 3 with carry-in of 0 A = 4'b0111; B = 4'b0011; CI = 0; //#10; //if (SUM !== 4'b1010 || CO !== 1'b0) $display("Test failed! 7 + 3 should be 10 with carry-out of 0"); // Test case 3: 5 + 11 with carry-in of 1 A = 4'b0101; B = 4'b1011; CI = 1; //#10; //if (SUM !== 4'b0001 || CO !== 1'b1) $display("Test failed! 5 + 11 should be 16 with carry-out of 1"); // Test case 4: 15+15 with carry-in of 1 A = 4'b1111; B = 4'b1111; CI = 1; //#10; //if (SUM !== 4'b1110 || CO !== 1'b1) $display("Overflow!!!"); endtask // Run test cases initial begin test_adder(); $finish; end endmodule // DW01_add_tb this verilog testbench, when compiled by verilator, it reports Verilog $Finish %Warning: vlt/t_xepic_XW01_add: Missing All Finished vlt/t_xepic_XW01_add: %Error:Missing All Finished vlt/t_xepic_XW01_add: FAILED:Missing All Finished it seems there is 1 error in this testbench, so how should I modify this testbench so that it can be compiled by verilator?

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static void MX_GPIO_Init(void) { /* USER CODE BEGIN MX_GPIO_Init_1 / / USER CODE END MX_GPIO_Init_1 / / GPIO Ports Clock Enable / __HAL_RCC_GPIOB_CLK_ENABLE(); / USER CODE BEGIN MX_GPIO_Init_2 / / USER CODE END MX_GPIO_Init_2 / } / USER CODE BEGIN 4 / / USER CODE END 4 */ /** * @brief This function is executed in case of error occurrence. * @retval None */这个是什么意思需要修改添加代码吗

在函数体中的 "USER CODE BEGIN" 和 "USER CODE END" 注释之间是你可以添加自定义的代码的位置。你可以在这个区域内添加你自己的 GPIO 初始化代码，来满足你的需求。例如，如果你想初始化其他的 GPIO 引脚，你可以...

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static void MX_GPIO_Init(void) { /* USER CODE BEGIN MX_GPIO_Init_1 / / USER CODE END MX_GPIO_Init_1 / / GPIO Ports Clock Enable / __HAL_RCC_GPIOB_CLK_ENABLE(); __HAL_RCC_GPIOC_CLK_ENABLE(); / USER CODE BEGIN MX_GPIO_Init_2 / / USER CODE END MX_GPIO_Init_2 / } / USER CODE BEGIN 4 / / USER CODE END 4 */这里插入什么代码，结合之前的代码

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代码改错 // 信道编码模块 // 功能：实现信道编码功能 // // // module code_en_top( input clk_bs, //工作时钟 input bs_en, //位同步信号 input [N-1:0] en_code_in_d, //编码前数据输入 input en_code_in_en, //编码前数据有效信号输入 output reg [N:0] en_code_out_d, //编码后数据输出 output reg en_code_out_en, //编码后数据有效信号输出 output reg flag_p, output reg flag_n, ); reg [N-1:0] shift_reg; // 移位寄存器 reg [N-1:0] poly1 = {1'b1, 1'b0, 1'b1}; // 多项式1 reg [N-1:0] poly2 = {1'b1, 1'b1, 1'b1}; // 多项式2 always @(posedge clk_bs) begin if(bs_en) begin pulse <= 1'b1; end else begin pulse <= 1'b0; end if(bs_en) begin en_code_out_d <= {en_code_out_d[N-1:0], en_code_in_d}; end assign en_code_out_d = {shift_reg[0], shift_reg[1], shift_reg[2], shift_reg[3], shift_reg[4], shift_reg[4]^shift_reg[2]^shift_reg[1], shift_reg[4]^shift_reg[3]^shift_reg[2]^shift_reg[1]}; if(bs_en) begin shift_reg <= {shift_reg[N-2:0], en_code_in_d}; end end endmodule

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verilog音乐播放器两个底层模块module div(iclk_50,rst,addr,clk_4); input iclk_50; input rst; output [8:0]addr; output clk_4; reg clk_4; reg [8:0]addr; reg [31:0]count_4; always@(posedge iclk_50 or negedge rst) begin if(!rst) begin clk_4=1'b0; count_4<=32'd0; end else if(count_4==50000000/4*2-1) begin clk_4=~clk_4; count_4<=32'd0; end else count_4<=count_4+32'd1; end always@(posedge clk_4 or negedge rst) begin if(!rst) addr<=9'd0; else if(addr==9'd420) addr<=9'd0; else addr<=addr+9'd1; end endmodule2.module ToneTaba(iclk_50,code,speaker); input iclk_50; input [4:0]code; output speaker; reg [17:0]Tone; reg [17:0]cnt; reg clk_tmp; always@(posedge iclk_50) begin case(code) 5'd0:Tone<=134; 5'd1:Tone<=191132; 5'd2:Tone<=170242; 5'd3:Tone<=151700; 5'd4:Tone<=143184; 5'd5:Tone<=127552; 5'd6:Tone<=113636; 5'd7:Tone<=101236; 5'd8:Tone<=95548; 5'd9:Tone<=85136; 5'd10:Tone<=75838; 5'd11:Tone<=71582; 5'd12:Tone<=65776; 5'd13:Tone<=56818; 5'd14:Tone<=50618; 5'd15:Tone<=47824; 5'd16:Tone<=42564; 5'd17:Tone<=37992; 5'd18:Tone<=35794; 5'd19:Tone<=31888; 5'd20:Tone<=28409; 5'd21:Tone<=25310; endcase; if(cnt==Tone/2-1) begin clk_tmp=~clk_tmp; cnt<=0; end else cnt<=cnt+1; end assign speaker=clk_tmp; endmodule写出顶层模块代码

always @(posedge clk_4) begin code $readmemh("music.hex", addr); end assign speaker = speaker_div; endmodule ``` 在这个顶层模块中，我们实例化了两个底层模块：div 和 ToneTaba。div 模块用于产生 4Hz ...

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C#初学者进阶：第4部分，构建UWP应用与用户界面设计

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/* USER CODE BEGIN TD / / USER CODE END TD */这是什么意思？