GABAergic麻醉下脑电图的排列Lempel-Ziv复杂性测量

研究论文
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"Permutation Lempel–Ziv complexity measure of electroencephalogram in GABAergic anaesthetics" 这篇研究论文探讨了在使用GABAergic（γ-氨基丁酸能）麻醉剂期间，通过Permutation Lempel-Ziv (PLZ) 复杂性度量方法来分析电encephalogram（脑电图，EEG）的技术。GABAergic麻醉剂是一种常见的神经递质系统，主要在麻醉和镇静过程中发挥作用，通过增强大脑中的GABA受体活性来调节神经活动。 Permutation Lempel-Ziv复杂性是信息理论和时间序列分析中的一个概念，它是一种衡量序列复杂性的非线性方法。在EEG分析中，这种方法可以帮助研究人员理解大脑活动的复杂性和有序性。在麻醉状态下，EEG的波形会发生变化，反映出大脑功能的改变。PLZ复杂性度量可以量化这些变化，提供对大脑状态的深入洞察，特别是在深度麻醉和意识丧失时。 论文指出，通过分析PLZ复杂性，可以评估GABAergic麻醉剂对大脑活动的影响，可能有助于优化麻醉深度的控制，确保患者在手术过程中处于适当的麻醉状态。此外，该技术还可能揭示麻醉剂如何改变大脑的信息处理能力，以及可能与意识丧失相关的神经动力学模式。 在研究方法上，作者可能采用了数据收集、EEG信号处理、PLZ算法应用以及统计分析等步骤。他们可能对比了不同麻醉深度下的EEG PLZ复杂性，以及与传统麻醉监测指标（如BIS指数）的关系。这项研究的结果可能有助于临床医生更好地理解和预测患者在麻醉过程中的反应，从而提高手术的安全性和效率。 论文的发表日期为2015年11月，作者来自中国燕山大学的电气工程研究所和新西兰怀卡托医院的麻醉科。论文经过了审稿和修改，最终被《生理测量》（Physiological Measurement）期刊接收并发表。作者们提供了联系方式，表明他们愿意进一步讨论研究细节和可能的合作。 这篇论文揭示了在GABAergic麻醉条件下，利用Permutation Lempel-Ziv复杂性度量技术对EEG进行分析的新方法，为理解麻醉作用机制及优化临床实践提供了有价值的研究工具。

Given a sequence of unique elements, a permutation of the sequence is a list containing the elements of the sequence in arbitrary order. For example, [2, 1, 3], [1, 3, 2], and [3, 2, 1] are some of the permutations of the sequence [1, 2, 3]. [] is the only permutations of []. Implement permutations, a generator function that takes in a sequence seq and returns a generator that yields all permutations of seq. Permutations may be yielded in any order. Note that the doctests test whether you are yielding all possible permutations, but not the order. The built-in sorted function takes in an iterable object and returns a list containing the elements of the iterable in non-decreasing order.

2023-06-01 上传
For each such subsequence permutation, the function yields a new permutation obtained by adding the removed element to the front of the subsequence permutation. Here are some examples of using the ...

You are given a positive integer nn. In this problem, the MEXMEX of a collection of integers c1,c2,…,ckc1,c2,…,ck is defined as the smallest positive integer xx which does not occur in the collection cc. The primality of an array a1,…,ana1,…,an is defined as the number of pairs (l,r)(l,r) such that 1≤l≤r≤n1≤l≤r≤n and MEX(al,…,ar)MEX⁡(al,…,ar) is a prime number. Find any permutation of 1,2,…,n1,2,…,n with the maximum possible primality among all permutations of 1,2,…,n1,2,…,n. Note: A prime number is a number greater than or equal to 22 that is not divisible by any positive integer except 11 and itself. For example, 2,5,132,5,13 are prime numbers, but 11 and 66 are not prime numbers. A permutation of 1,2,…,n1,2,…,n is an array consisting of nn distinct integers from 11 to nn in arbitrary order. For example, [2,3,1,5,4][2,3,1,5,4] is a permutation, but [1,2,2][1,2,2] is not a permutation (22 appears twice in the array), and [1,3,4][1,3,4] is also not a permutation (n=3n=3 but there is 44 in the array).

2023-07-14 上传
To find a permutation of 1, 2, ..., n with the maximum possible primality, we can use the following approach: 1. If n is 1, return [1] as the permutation. 2. If n is 2, return [2, 1] as the ...

Notice that the number 123456789 is a 9-digit number consisting exactly the numbers from 1 to 9, with no duplication. Double it we will obtain 246913578, which happens to be another 9-digit number consisting exactly the numbers from 1 to 9, only in a different permutation. Check to see the result if we double it again! Now you are suppose to check if there are more numbers with this property. That is, double a given number with k digits, you are to tell if the resulting number consists of only a permutation of the digits in the original number. Input Specification: Each input contains one test case. Each case contains one positive integer with no more than 20 digits. Output Specification: For each test case, first print in a line "Yes" if doubling the input number gives a number that consists of only a permutation of the digits in the original number, or "No" if not. Then in the next line, print the doubled number. Sample Input: 1234567899 Sample Output: Yes 2469135798

2023-05-27 上传
If they match, then the doubled number consists of only a permutation of the digits in the original number; otherwise, it does not. Here's the Python code: ```python num = input().strip() double_...

写一段c++代码You are given an unsorted permutation p_1, p_2, \ldots, p_np 1 ​ ,p 2 ​ ,…,p n ​ . To sort the permutation, you choose a constant kk (k \ge 1k≥1) and do some operations on the permutation. In one operation, you can choose two integers ii, jj (1 \le j < i \le n1≤j<i≤n) such that i - j = ki−j=k, then swap p_ip i ​ and p_jp j ​ . What is the maximum value of kk that you can choose to sort the given permutation? A permutation is an array consisting of nn distinct integers from 11 to nn in arbitrary order. For example, [2, 3, 1, 5, 4][2,3,1,5,4] is a permutation, but [1, 2, 2][1,2,2] is not a permutation (22 appears twice in the array) and [1, 3, 4][1,3,4] is also not a permutation (n = 3n=3 but there is 44 in the array). An unsorted permutation pp is a permutation such that there is at least one position ii that satisfies p_i \ne ip i ​  =i.

2023-06-01 上传
The code reads in the input permutation, then iterates over the possible values of k in descending order from n/2 to 1. For each value of k, it sorts each k-length block separately using a simple ...

input n(1<=n<=7);and some integers,ouput the Permutation of these integers in ascending order.

2023-04-05 上传
If the sorted list is empty, append the current permutation to the list of permutations. d. Otherwise, call the recursive function with the updated sorted list and empty list. e. Remove the current...

pop = np.vstack([np.random.permutation(DNA_size) for _ in range(POP_size)])

2023-03-31 上传
As an AI language model, I don't have...In other words, this line generates a population of `POP_size` individuals, where each individual is a random permutation of the DNA sequence of length `DNA_size`.

写出这个题的代码：You are given an unsorted permutation p1,p2,…,pn. To sort the permutation, you choose a constant k (k≥1) and do some operations on the permutation. In one operation, you can choose two integers i, j (1≤j<i≤n) such that i−j=k, then swap pi and pj. What is the maximum value of k that you can choose to sort the given permutation? A permutation is an array consisting of n distinct integers from 1 to n in arbitrary order. For example, [2,3,1,5,4] is a permutation, but [1,2,2] is not a permutation (2 appears twice in the array) and [1,3,4] is also not a permutation (n=3 but there is 4 in the array). An unsorted permutation p is a permutation such that there is at least one position i that satisfies pi≠i. Input Each test contains multiple test cases. The first line contains the number of test cases t (1≤t≤104). The description of the test cases follows. The first line of each test case contains a single integer n (2≤n≤105) — the length of the permutation p. The second line of each test case contains n distinct integers p1,p2,…,pn (1≤pi≤n) — the permutation p. It is guaranteed that the given numbers form a permutation of length n and the given permutation is unsorted. It is guaranteed that the sum of n over all test cases does not exceed 2⋅105. Output For each test case, output the maximum value of k that you can choose to sort the given permutation. We can show that an answer always exists.

2023-05-15 上传
``` #include using namespace std; int main() { int t; scanf("%d", &t); while(t--) { int n; scanf("%d", &n); vector<int> p(n); for(int i = 0; i ; i++) { scanf("%d", &p[i]);...```

You are given a positive integer n . In this problem, the MEX of a collection of integers c1,c2,…,ck is defined as the smallest positive integer x which does not occur in the collection c . The primality of an array a1,…,an is defined as the number of pairs (l,r) such that 1≤l≤r≤n and MEX(al,…,ar) is a prime number. Find any permutation of 1,2,…,n with the maximum possible primality among all permutations of 1,2,…,n . Note: A prime number is a number greater than or equal to 2 that is not divisible by any positive integer except 1 and itself. For example, 2,5,13 are prime numbers, but 1 and 6 are not prime numbers. A permutation of 1,2,…,n is an array consisting of n distinct integers from 1 to n in arbitrary order. For example, [2,3,1,5,4] is a permutation, but [1,2,2] is not a permutation (2 appears twice in the array), and [1,3,4] is also not a permutation (n=3 but there is 4 in the array). Input Each test contains multiple test cases. The first line contains the number of test cases t (1≤t≤104 ). The description of the test cases follows. The only line of each test case contains a single integer n (1≤n≤2⋅105 ). It is guaranteed that the sum of n over all test cases does not exceed 2⋅105 . Output For each test case, output n integers: a permutation of 1,2,…,n that achieves the maximum possible primality. If there are multiple solutions, print any of them. 用c++如何实现，并写出题解

2023-07-12 上传
swap(permutation[n-1], permutation[n-2]); } // 将质数放在前面，非质数放在后面 for (int i = 2; i ; i++) { if (isPrime(i)) { swap(permutation[i-1], permutation[n-1]); break; } } return ...

next_permutation

2023-04-02 上传
In other words, it rearranges the elements of a sequence in such a way that the lexicographically next higher permutation is obtained. If the current sequence is already the highest possible ...

You are given a permutation† a of length n . Find any permutation b of length n such that a1+b1≤a2+b2≤a3+b3≤…≤an+bn . It can be proven that a permutation b that satisfies the condition above always exists. † A permutation of length n is an array consisting of n distinct integers from 1 to n in arbitrary order. For example, [2,3,1,5,4] is a permutation, but [1,2,2] is not a permutation (2 appears twice in the array), and [1,3,4] is also not a permutation (n=3 but there is 4 in the array). Input Each test contains multiple test cases. The first line of input contains a single integer t (1≤t≤2000 ) — the number of test cases. The description of test cases follows. The first line of each test case contains a single integer n (1≤n≤100 ) — the length of permutations a and b . The second line of each test case contains n distinct integers a1,a2,…,an (1≤ai≤n ) — the elements of permutation a . All elements of a are distinct. Note that there is no bound on the sum of n over all test cases. Output For each test case, output any permutation b which satisfies the constraints mentioned in the statement. It can be proven that a permutation b that satisfies the condition above always exists.

2023-05-29 上传
题目翻译： 给定一个长度为 n 的排列 a，找到任意一个长度为 n 的排列 b，使得 a1+b1≤a2+b2≤a3+b3≤…≤an+bn。可以证明，满足上述条件的排列 b 总是存在的。 输入： 第一行输入一个整数 t，表示测试数据组数。...
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