void game() { int seconds = 59; while() while (1) { cleardevice(); update(); putimage(zuoqishi + mouse.y * size, shangqishi + mouse.x * size, &bgs[2]); char key = _getch(); switch (key) { case 72: case 'W': case 'w': if (mouse.x - 1 >= 0 && mapp[mouse.x - 1][mouse.y] != 0&& mapp[mouse.x - 1][mouse.y] != 2) { mouse.x--; } else if (mapp[mouse.x - 1][mouse.y] == 2) { } break;//上 case 80: case 'S': case 's': if (mouse.x + 1 < ck && mapp[mouse.x + 1][mouse.y] != 0) { mouse.x++; } break;//下 case 75: case 'A': case 'a': if (mouse.y - 1 >= 0 && mapp[mouse.x][mouse.y - 1] != 0) { mouse.y--; } break;//左 case 77: case 'D': case 'd': if (mouse.y + 1 < ck && mapp[mouse.x][mouse.y + 1] != 0) { mouse.y++; } break;//右 } Sleep(1000); seconds--; cout << seconds << endl; } endgame(); }怎样完成这段代码使得在按键操作的同时进行1分钟的倒计时
时间: 2023-12-20 19:07:19 浏览: 208
天津理工大学通信技术实验报告1(内含完整代码)
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你可以在 `while(1)` 循环中加入一个计时器,每一秒钟减少一次剩余时间,并在屏幕上显示。当剩余时间为0时,跳出循环并执行 `endgame()` 函数。
修改后的代码如下:
```
void game() {
int seconds = 60; // 设置游戏时间为60秒
while(1) {
cleardevice();
update();
putimage(zuoqishi + mouse.y * size, shangqishi + mouse.x * size, &bgs[2]);
char key = _getch();
switch (key) {
case 72:
case 'W':
case 'w':
if (mouse.x - 1 >= 0 && mapp[mouse.x - 1][mouse.y] != 0 && mapp[mouse.x - 1][mouse.y] != 2) {
mouse.x--;
} else if (mapp[mouse.x - 1][mouse.y] == 2) {
// do something
}
break; //上
case 80:
case 'S':
case 's':
if (mouse.x + 1 < ck && mapp[mouse.x + 1][mouse.y] != 0) {
mouse.x++;
}
break; //下
case 75:
case 'A':
case 'a':
if (mouse.y - 1 >= 0 && mapp[mouse.x][mouse.y - 1] != 0) {
mouse.y--;
}
break; //左
case 77:
case 'D':
case 'd':
if (mouse.y + 1 < ck && mapp[mouse.x][mouse.y + 1] != 0) {
mouse.y++;
}
break; //右
}
Sleep(1000); // 等待一秒钟
seconds--; // 剩余时间减一秒
cout << "剩余时间:" << seconds << " 秒" << endl;
if (seconds == 0) { // 时间到了,跳出循环
break;
}
}
endgame();
}
```
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